Bitwise operation and usage

One typical usage:

| is used to set a certain bit to 1

& is used to test or clear a certain bit

• Set a bit (where n is the bit number, and 0 is the least significant bit):

  unsigned char a |= (1 << n);

• Clear a bit:

  unsigned char b &= ~(1 << n);

• Toggle a bit:

  unsigned char c ^= (1 << n);

• Test a bit:

  unsigned char e = d & (1 << n);

Take the case of your list for example:

x | 2 is used to set bit 1 of x to 1

x & 1 is used to test if bit 0 of x is 1 or 0

I hope this clarifies those two:

x | 2

0001 //x
0010 //2

0011 //result = 3

---

x & 1

0001 //x
0001 //1

0001 //result = 1

Think of 0 as false and 1 as true. Then bitwise and(&) and or(|) work just like regular and and or except they do all of the bits in the value at once. Typically you will see them used for flags if you have 30 options that can be set (say as draw styles on a window) you don’t want to have to pass in 30 separate boolean values to set or unset each one so you use | to combine options into a single value and then you use & to check if each option is set. This style of flag passing is heavily used by OpenGL. Since each bit is a separate flag you get flag values on powers of two(aka numbers that have only one bit set) 1(2^0) 2(2^1) 4(2^2) 8(2^3) the power of two tells you which bit is set if the flag is on.

Also note 2 = 10 so x|2 is 110(6) not 111(7) If none of the bits overlap(which is true in this case) | acts like addition.

what are bitwise operators actually used for? I’d appreciate some examples.

One of the most common uses of bitwise operations is for parsing hexadecimal colours.

For example, here’s a Python function that accepts a String like #FF09BE and returns a tuple of its Red, Green and Blue values.

def hexToRgb(value):
    # Convert string to hexadecimal number (base 16)
    num = (int(value.lstrip("#"), 16))

    # Shift 16 bits to the right, and then binary AND to obtain 8 bits representing red
    r = ((num >> 16) & 0xFF)

    # Shift 8 bits to the right, and then binary AND to obtain 8 bits representing green
    g = ((num >> 8) & 0xFF)

    # Simply binary AND to obtain 8 bits representing blue
    b = (num & 0xFF)
    return (r, g, b)

I know that there are more efficient ways to acheive this, but I believe that this is a really concise example illustrating both shifts and bitwise boolean operations.

Another common use-case is manipulating/testing file permissions. See the Python stat module: http://docs.python.org/library/stat.html.

For example, to compare a file’s permissions to a desired permission set, you could do something like:

import os
import stat

#Get the actual mode of a file
mode = os.stat('file.txt').st_mode

#File should be a regular file, readable and writable by its owner
#Each permission value has a single 'on' bit.  Use bitwise or to combine 
#them.
desired_mode = stat.S_IFREG|stat.S_IRUSR|stat.S_IWUSR

#check for exact match:
mode == desired_mode
#check for at least one bit matching:
bool(mode & desired_mode)
#check for at least one bit 'on' in one, and not in the other:
bool(mode ^ desired_mode)
#check that all bits from desired_mode are set in mode, but I don't care about 
# other bits.
not bool((mode^desired_mode)&desired_mode)

I cast the results as booleans, because I only care about the truth or falsehood, but it would be a worthwhile exercise to print out the bin() values for each one.

I didn’t see it mentioned above but you will also see some people use left and right shift for arithmetic operations. A left shift by x is equivalent to multiplying by 2^x (as long as it doesn’t overflow) and a right shift is equivalent to dividing by 2^x.

Recently I’ve seen people using x << 1 and x >> 1 for doubling and halving, although I’m not sure if they are just trying to be clever or if there really is a distinct advantage over the normal operators.

Bit representations of integers are often used in scientific computing to represent arrays of true-false information because a bitwise operation is much faster than iterating through an array of booleans. (Higher level languages may use the idea of a bit array.)

A nice and fairly simple example of this is the general solution to the game of Nim. Take a look at the Python code on the Wikipedia page. It makes heavy use of bitwise exclusive or, ^.

This example will show you the operations for all four 2 bit values:

10 | 12

1010 #decimal 10
1100 #decimal 12

1110 #result = 14

---

10 & 12

1010 #decimal 10
1100 #decimal 12

1000 #result = 8

Here is one example of usage:

x = raw_input('Enter a number:')
print 'x is %s.' % ('even', 'odd')[x&1]

I think that the second part of the question:

Also, what are bitwise operators actually used for? I’d appreciate some examples.

Has been only partially addressed. These are my two cents on that matter.

Bitwise operations in programming languages play a fundamental role when dealing with a lot of applications. Almost all low-level computing must be done using this kind of operations.

In all applications that need to send data between two nodes, such as:

• computer networks;

• telecommunication applications (cellular phones, satellite communications, etc).

In the lower level layer of communication, the data is usually sent in what is called frames. Frames are just strings of bytes that are sent through a physical channel. This frames usually contain the actual data plus some other fields (coded in bytes) that are part of what is called the header. The header usually contains bytes that encode some information related to the status of the communication (e.g, with flags (bits)), frame counters, correction and error detection codes, etc. To get the transmitted data in a frame, and to build the frames to send data, you will need for sure bitwise operations.

In general, when dealing with that kind of applications, an API is available so you don’t have to deal with all those details. For example, all modern programming languages provide libraries for socket connections, so you don’t actually need to build the TCP/IP communication frames. But think about the good people that programmed those APIs for you, they had to deal with frame construction for sure; using all kinds of bitwise operations to go back and forth from the low-level to the higher-level communication.

As a concrete example, imagine some one gives you a file that contains raw data that was captured directly by telecommunication hardware. In this case, in order to find the frames, you will need to read the raw bytes in the file and try to find some kind of synchronization words, by scanning the data bit by bit. After identifying the synchronization words, you will need to get the actual frames, and SHIFT them if necessary (and that is just the start of the story) to get the actual data that is being transmitted.

Another very different low level family of application is when you need to control hardware using some (kind of ancient) ports, such as parallel and serial ports. This ports are controlled by setting some bytes, and each bit of that bytes has a specific meaning, in terms of instructions, for that port (see for instance http://en.wikipedia.org/wiki/Parallel_port). If you want to build software that does something with that hardware you will need bitwise operations to translate the instructions you want to execute to the bytes that the port understand.

For example, if you have some physical buttons connected to the parallel port to control some other device, this is a line of code that you can find in the soft application:

read = ((read ^ 0x80) >> 4) & 0x0f; 

Hope this contributes.

There may be a better way to find where an array element is between two values, but as this example shows, the & works here, whereas and does not.

import numpy as np
a=np.array([1.2, 2.3, 3.4])
np.where((a>2) and (a<3))      
#Result: Value Error
np.where((a>2) & (a<3))
#Result: (array([1]),)

i didnt see it mentioned, This example will show you the (-) decimal operation for 2 bit values: A-B (only if A contains B)

this operation is needed when we hold an verb in our program that represent bits. sometimes we need to add bits (like above) and sometimes we need to remove bits (if the verb contains then)

111 #decimal 7
-
100 #decimal 4
--------------
011 #decimal 3

with python:
7 & ~4 = 3 (remove from 7 the bits that represent 4)

001 #decimal 1
-
100 #decimal 4
--------------
001 #decimal 1

with python:
1 & ~4 = 1 (remove from 1 the bits that represent 4 – in this case 1 is not ‘contains’ 4)..

Whilst manipulating bits of an integer is useful, often for network protocols, which may be specified down to the bit, one can require manipulation of longer byte sequences (which aren’t easily converted into one integer). In this case it is useful to employ the bitstring library which allows for bitwise operations on data – e.g. one can import the string ‘ABCDEFGHIJKLMNOPQ’ as a string or as hex and bit shift it (or perform other bitwise operations):

>>> import bitstring
>>> bitstring.BitArray(bytes='ABCDEFGHIJKLMNOPQ') << 4
BitArray('0x142434445464748494a4b4c4d4e4f50510')
>>> bitstring.BitArray(hex='0x4142434445464748494a4b4c4d4e4f5051') << 4
BitArray('0x142434445464748494a4b4c4d4e4f50510')

the following bitwise operators: &, |, ^, and ~ return values (based on their input) in the same way logic gates affect signals. You could use them to emulate circuits.

Sets

Sets can be combined using mathematical operations.

• The union operator | combines two sets to form a new one containing items in either.
• The intersection operator & gets items only in both.
• The difference operator - gets items in the first set but not in the second.
• The symmetric difference operator ^ gets items in either set, but not both.

Try It Yourself:

first = {1, 2, 3, 4, 5, 6}
second = {4, 5, 6, 7, 8, 9}

print(first | second)

print(first & second)

print(first - second)

print(second - first)

print(first ^ second)

Result:

{1, 2, 3, 4, 5, 6, 7, 8, 9}

{4, 5, 6}

{1, 2, 3}

{8, 9, 7}

{1, 2, 3, 7, 8, 9}

To flip bits (i.e. 1’s complement/invert) you can do the following:

Since value ExORed with all 1s results into inversion,
for a given bit width you can use ExOR to invert them.

In Binary
a=1010 --> this is 0xA or decimal 10
then 
c = 1111 ^ a = 0101 --> this is 0xF or decimal 15
-----------------
In Python
a=10
b=15
c = a ^ b --> 0101
print(bin(c)) # gives '0b101'

You can use bit masking to convert binary to decimal;

int a = 1 << 7;
int c = 55;
for(int i = 0; i < 8; i++){
    System.out.print((a & c) >> 7);     
    c = c << 1;
}

this is for 8 digits you can also do for further more.

Bit manipulation, in some cases, can obviate or reduce the need to loop over a data structure and can give many-fold speed-ups, as bit manipulations are processed in parallel, but the code can become more difficult to write and maintain.

1.Check the integer is even or odd.

def even_or_odd(num):                                   
    if (num & 1) == 0:                                               
        return f"{num} is even number"                          
    else:                                                        
        return f"{num} is odd number"
 

2.Multiply by 2 using the left shift operator:

print(7 << 1)                     
    output: 14  



 

3.Divide 2 using the right shift operator:

print(14 >> 1)              
 output: 7   

4.One’s complement operator (~): If we want to invert every bit of a number i.e change bit ‘0’ to ‘1’ and bit ‘1’ to ‘0’.

num = 7
print(~num)                     
output: -8 

5.Two’s complement of the number:

num = 5                                                                            

twos_complement = -num                                                          

print(f"This is two's complement {twos_complement}")                            

print(f"This is also two's complement {~num + 1}")   

6.Upper case English alphabet to lower case: ch |= ‘ ‘
This mask is bit representation of space character (‘ ‘).

ch = ‘A’        #(01000001)         
mask = ‘ ‘      #(00100000)     
ch | mask = ‘a’ #(01100001) 

7.Lower case English alphabet to upper case: ch &= ‘’
This mask is a bit representation of the underscore character (‘‘). The character ‘ch’ then AND with mask.

ch = ‘a’             #(01100001)     
mask = ‘_ ‘          #(11011111)           
ch & mask = ‘A’      #(01000001) 

8.A number is a power of 2.

  x and (not(x & (x - 1)))

9.The Quickest way to swap two numbers.

 a = a ^ b

10.Count set bits in an integer.

def  countSetBits(n):                                      

    count = 0                                              

    while (n):                                               

        count += n & 1                                               

        n >>= 1                     

    return count  

Maybe you can use bin() function.

print(bin(15).count('1'))
# output 4

Brian Kernighan’s Algorithm: If we do n & (n-1) in a loop and count the number of times the loop executes, we get the set bit count.

def countSetBits(n):                                                 

    count = 0                                                       

    while (n):                                                       

        n &= (n-1)                                                   

        count += 1                                                                       

    return count   

11.Count unset bits of a number.

def countunsetbits(n):                                                    

    count = 0                                                                                            



    x = 1                                                                                       

    while(x < n + 1):                                                   

        if ((x & n) == 0):                                 

            count += 1                                              

        x = x << 1                                                   

    return count   

12. Toggle all bits after the most significant bit

    def toggle(n):

    temp = 1                                                                              
    
    while (temp <= n):                                                                            
    
        n = n ^ temp                                              
    
    
        temp = temp << 1                                     
    return n