Python list equivalent in C++?

Question

Could you please tell me what is the closest data type in C++ to python list? If there is nothing similar, how would you build it in C++?

Asked By: gen

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Source

Answer 1

Maybe storing boost::any in a std::vector?
http://www.boost.org/doc/libs/1_54_0/doc/html/boost/any.html

Here is a simple working example. See James comments below too.

#include "../boost_1_54_0/boost/any.hpp"
#include <vector>
#include <string>
#include <iostream>

int main()
{
    std::vector<boost::any> myList;

    myList.push_back(std::string("Hello"));
    myList.push_back(10);
    myList.push_back(std::string("World"));

    std::string any1 = boost::any_cast<std::string> (myList[0]);
    int any2 = boost::any_cast<int> (myList[1]);
    std::string any3 = boost::any_cast<std::string> (myList[2]);

    std::cout<<any1<<" "<<any2<<" "<<any3<<std::endl;

    return 0;
}

Answered By: Korchkidu

Answer 2

If you’re looking for standard one-dimensional data structures idiomatic to C++, std::vectors, std::lists, and arrays (or std::arrays) all have features similar to Python lists. Which of those data structure you want to choose depends on your requirements. std::vector is a very reasonable structure to default to if you’re just looking to store a collection of items.

These data structures all require that each element is of the same type. Generally in C++ that is what you want. However, if you’re specifically looking to store a variety of types in the same structure, there are a few options:

You can store void pointers. You will, however, need some way to figure out the type of each element and cast the pointer to the appropriate type to use each element.
If you have a specific set of types you wish to store, you can declare a union (which you’d generally wrap in a struct along with an enum to indicate the type being stored).

Answered By: Eric Finn

Answer 3

Actually no C++ container is equivalent to Python’s list, which is partially a result of the very different object models of C++ and Python. In particular, the suggested and upvoted std::list is IMHO not even close to Python’s list type, a I’d rather suggest std::vector or maybe std::deque. That said, it isn’t clear what exactly it is that you want and how to “build it” strongly depends on what exactly “it” is, i.e. what you expect from the container.

I’d suggest you take a look at the C++ containers std::vector, std::deque and std::list to get an overview. Then look at things like Boost.Any and Boost.Variant that you can combine with them, maybe also one of the smart pointers and Boost.Optional. Finally, check out Boost.Container and Boost.Intrusive. If the unlikely case that none of these provide a suitable approximation, you need to provide a better explanation of what your actual goals are.

Answered By: doomster

Answer 4

There is no real equivalent, and it would be extremely difficult
to provide one. Python and C++ are radically different
languages, and providing one really wouldn’t make much sense in
the context of C++. The most important differences are that
everything in Python is dynamically allocated, and is an
“object”, and that Python uses duck typing.

FWIW: one very early library (before templates) in C++ did offer
containers of Object*, with derived classes to box int,
double, etc. Actual experience showed very quickly that it
wasn’t a good idea. (And I’m curious: does any one else
remember it? And particularly, exactly what it was
called—something with NHS in it, but I can’t remember more.)

Answered By: James Kanze

Answer 5

I am working on a wrapper for std::vector that makes it more like Python’s lists named pylistpp. The API is just like Python. Example:

#include <list.hpp>
#include <iostream>

int main()
{
    list<int> mylist;
    mylist.append(5);
    mylist.append(7);
    int count = mylist.count(5);
    std::cout << count << std::endl;
    std::cout << mylist.pop(0) << std::endl;
    std::cout << mylist.index(7);
    return 0;
}

Answered By: kirbyfan64sos

Python list equivalent in C++?

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