Does Python have a function to reduce fractions?
Question:
For example, when I calculate 98/42
I want to get 7/3
, not 2.3333333
, is there a function for that using Python or Numpy
?
Answers:
The fractions
module can do that
>>> from fractions import Fraction
>>> Fraction(98, 42)
Fraction(7, 3)
There’s a recipe over here for a numpy gcd. Which you could then use to divide your fraction
>>> def numpy_gcd(a, b):
... a, b = np.broadcast_arrays(a, b)
... a = a.copy()
... b = b.copy()
... pos = np.nonzero(b)[0]
... while len(pos) > 0:
... b2 = b[pos]
... a[pos], b[pos] = b2, a[pos] % b2
... pos = pos[b[pos]!=0]
... return a
...
>>> numpy_gcd(np.array([98]), np.array([42]))
array([14])
>>> 98/14, 42/14
(7, 3)
Addition to John’s answer:
To get simplified fraction from a decimal number (say 2.0372856077554062)
Using Fraction gives the following output:
Fraction(2.0372856077554062)
#> Fraction(4587559351967261, 2251799813685248)
To get simplified answer :
Fraction(2.0372856077554062).limit_denominator()
#> Fraction(2732, 1341)
This python code uses only the math module
"""
import math
def _fractions_(numerator, denominator):
if math.gcd(numerator, denominator) == denominator:
return int(numerator/denominator)
elif math.gcd(numerator, denominator) == 1:
return str(numerator) + "/" + str(denominator)
else:
top = numerator / math.gcd(numerator, denominator)
bottom = denominator / math.gcd(numerator, denominator)
return str(top) + "/" + str(bottom)
print(_fractions_(46,23))
print(_fractions_(34,25))
print(_fractions_(24, 28))
"""
Does Python have a function to reduce fractions?
No there is no built-in or external function, still you have two solutions.
1. Using fractions
module
You can use Fraction
objects from fractions
module. From the documentation:
from fractions import Fraction
Fraction(16, -10)
>>> Fraction(-8, 5)
In this module a fraction is implicitly reduced, you can get the numerator and the denominator:
a = 16
b = -10
q = Fraction(a, b)
a = q.numerator
b = q.denominator
print (f'{q} == {a}/{b}')
>>> -8/5 == -8/5
2. Reduction using the GCD
Any fraction can be reduced using the GCD, greatest common factor, of numerator and denominator: a/b == (a/gcd)/(b/gcd)
.
GCD function is available both from numpy
and math
modules:
import numpy as np
a = 98
b = 42
gcd = np.gcd(a, b)
print(f'{a}/{b} == {int(a/gcd)}/{int(b/gcd)}')
`>>> 98/42 == 7/3
There is an alternative, but I do not consider it as valid for common needs: Use symbolic math with module sympy.
This allows to work with exact numbers at the cost of a loss of efficiency. sympy
is it’s own world and some learning time is required.
For example, when I calculate 98/42
I want to get 7/3
, not 2.3333333
, is there a function for that using Python or Numpy
?
The fractions
module can do that
>>> from fractions import Fraction
>>> Fraction(98, 42)
Fraction(7, 3)
There’s a recipe over here for a numpy gcd. Which you could then use to divide your fraction
>>> def numpy_gcd(a, b):
... a, b = np.broadcast_arrays(a, b)
... a = a.copy()
... b = b.copy()
... pos = np.nonzero(b)[0]
... while len(pos) > 0:
... b2 = b[pos]
... a[pos], b[pos] = b2, a[pos] % b2
... pos = pos[b[pos]!=0]
... return a
...
>>> numpy_gcd(np.array([98]), np.array([42]))
array([14])
>>> 98/14, 42/14
(7, 3)
Addition to John’s answer:
To get simplified fraction from a decimal number (say 2.0372856077554062)
Using Fraction gives the following output:
Fraction(2.0372856077554062)
#> Fraction(4587559351967261, 2251799813685248)
To get simplified answer :
Fraction(2.0372856077554062).limit_denominator()
#> Fraction(2732, 1341)
This python code uses only the math module
"""
import math
def _fractions_(numerator, denominator):
if math.gcd(numerator, denominator) == denominator:
return int(numerator/denominator)
elif math.gcd(numerator, denominator) == 1:
return str(numerator) + "/" + str(denominator)
else:
top = numerator / math.gcd(numerator, denominator)
bottom = denominator / math.gcd(numerator, denominator)
return str(top) + "/" + str(bottom)
print(_fractions_(46,23))
print(_fractions_(34,25))
print(_fractions_(24, 28))
"""
Does Python have a function to reduce fractions?
No there is no built-in or external function, still you have two solutions.
1. Using fractions
module
You can use Fraction
objects from fractions
module. From the documentation:
from fractions import Fraction
Fraction(16, -10)
>>> Fraction(-8, 5)
In this module a fraction is implicitly reduced, you can get the numerator and the denominator:
a = 16
b = -10
q = Fraction(a, b)
a = q.numerator
b = q.denominator
print (f'{q} == {a}/{b}')
>>> -8/5 == -8/5
2. Reduction using the GCD
Any fraction can be reduced using the GCD, greatest common factor, of numerator and denominator: a/b == (a/gcd)/(b/gcd)
.
GCD function is available both from numpy
and math
modules:
import numpy as np
a = 98
b = 42
gcd = np.gcd(a, b)
print(f'{a}/{b} == {int(a/gcd)}/{int(b/gcd)}')
`>>> 98/42 == 7/3
There is an alternative, but I do not consider it as valid for common needs: Use symbolic math with module sympy.
This allows to work with exact numbers at the cost of a loss of efficiency. sympy
is it’s own world and some learning time is required.