Invalid Syntax error?
Question:
I’m new at Python and tried writing a basic script.
I’m trying to print out all the letters of the alphabet, and I keep getting Invalid Syntax.
letter = ord('a')
while letter != ord('z')
print(chr(letter))
letter = letter + 1
Here’s the first error log:
while letter != ord('z')
^
SyntaxError: invalid syntax
It seemed that Python doesn’t like closing parentheses, so when I removed it, it gave me this:
print(chr(letter))
^
SyntaxError: invalid syntax
I couldn’t do anything to fix this one, so I tried removing the line entirely. It then gave me this:
letter = letter + 1
^
SyntaxError: invalid syntax
I have no idea what I’m doing at this point, and only after deleting the entire script altogether was Python finally happy.
How do I fix the script so it doesn’t get any more Invalid Syntaxes?
Answers:
Missing the colon in end while loop.
letter = ord('a')
while letter != ord('z'):
print(chr(letter))
letter += 1
You want a colon at the end of your while loop, to let Python know it’s a block.
while letter != ord('z'):
<rest of your code here>
Also, right now you seem to have the start of the while loop indented and none of the rest, when you want the opposite: all the code to be run in the while loop should be indented, but the header shouldn’t be.
As a side note, your ord and chr strategy is totally valid but probably more complicated than necessary. In Python, a for loop can iterate through a string as well as a range of numbers. So you can say
for character in "abcdefghijklmnopqrstuvwxyz":
print(character)
A shorter way to get that alphabet string is
import string
string.lowercase
I’m new at Python and tried writing a basic script.
x = input("ecrit ton premier nomber :")
z = input("ecrit ton Processus :")
y = input("ecrit ton deuxieme nombre :")
if z == + :
print(x+y)
Here’s the error log:
if z == + :
^
SyntaxError: invalid syntax
I’m new at Python and tried writing a basic script.
I’m trying to print out all the letters of the alphabet, and I keep getting Invalid Syntax.
letter = ord('a')
while letter != ord('z')
print(chr(letter))
letter = letter + 1
Here’s the first error log:
while letter != ord('z')
^
SyntaxError: invalid syntax
It seemed that Python doesn’t like closing parentheses, so when I removed it, it gave me this:
print(chr(letter))
^
SyntaxError: invalid syntax
I couldn’t do anything to fix this one, so I tried removing the line entirely. It then gave me this:
letter = letter + 1
^
SyntaxError: invalid syntax
I have no idea what I’m doing at this point, and only after deleting the entire script altogether was Python finally happy.
How do I fix the script so it doesn’t get any more Invalid Syntaxes?
Missing the colon in end while loop.
letter = ord('a')
while letter != ord('z'):
print(chr(letter))
letter += 1
You want a colon at the end of your while loop, to let Python know it’s a block.
while letter != ord('z'):
<rest of your code here>
Also, right now you seem to have the start of the while loop indented and none of the rest, when you want the opposite: all the code to be run in the while loop should be indented, but the header shouldn’t be.
As a side note, your ord and chr strategy is totally valid but probably more complicated than necessary. In Python, a for loop can iterate through a string as well as a range of numbers. So you can say
for character in "abcdefghijklmnopqrstuvwxyz":
print(character)
A shorter way to get that alphabet string is
import string
string.lowercase
I’m new at Python and tried writing a basic script.
x = input("ecrit ton premier nomber :")
z = input("ecrit ton Processus :")
y = input("ecrit ton deuxieme nombre :")
if z == + :
print(x+y)
Here’s the error log:
if z == + :
^
SyntaxError: invalid syntax