Python – all lottery combinations – no duplicates, in order

Question

I’ve wrote a script to print out lottery combinations. What i’m aiming for is this: There are 6 numbers in the lottery between 1-49 meaning there are 13,983,816 combinations. I want to print out all combinations IN ORDER whilst making sure there are NO duplicates.

Here is my code so far:

import random
numbers = []
for i in range(2):
    for j in range(6):
        numbers.append(random.randint(1,49))
        for k in range(j):
            while numbers[j]==numbers[k]:
                numbers[j]=random.randint(1,49)
    print sorted(numbers)
    numbers = []
f = open('combinations.txt', 'w')
f.write(str(sorted(numbers)))

The problems are:

The output in the terminal is:

[18, 20, 27, 32, 44, 48]
[5, 7, 10, 13, 33, 45]

I want to start with [1,2,3,4,5,6] and end up at [44,45,46,47,48,49]. So I need to order the results.

Also, I’ve tried converting the list to a string so I can put the results in a big text file, but I’m just printing [] to the text file at the moment.

Asked By: BubbleMonster

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Source

Answer 1

Use itertools.combinations:

>>> from itertools import combinations
>>> for comb in combinations(range(1,50), 6):
...     print comb      #Hit Enter at your own risk

For printing the combinations to the text file:

with open('combinations.txt', 'w') as f:
   for comb in combination:
       f.write(str(comb) + 'n')

Answered By: Ashwini Chaudhary

Answer 2

You were clearing your list then writing to the file.

from itertools import combinations
f = open('combinations.txt', 'w')
for comb in combinations(range(1,50), 6):
    f.write(str(comb))
    f.write('n')
f.close()

But make sure you have at least 350 Megabytes of disk space free! and some time to spare.

(348168480 bytes I checked with:

>>> s = 0
>>> for comb in combinations(range(1,50), 6):
...    s += len(repr(comb))+2
... 
>>> s
348168480

).

Answered By: Steve Barnes

Answer 3

**import itertools
f= open('combinations.txt','w')
numb = [1,2,3,4,5,6,7]
it = itertools.combinations(numb,3)
for x in it:
    f.write(str(x))
    f.write('n')
f.close()**

There you go, just add as many numbers to numb and change the it variable to correspondent of r

Answered By: Adam Pope

Answer 4

import time
from datetime import timedelta

start_time = time.time()

from itertools import combinations
comb_list = list(combinations(range(1, 50), 6))
start_index = comb_list.index((1, 2, 3, 4, 5, 6))
counter = 0

for i, comb in enumerate(comb_list[start_index:]):
    print(f"Combination {i+1}: {comb}")
    counter += 1

end_time = time.time()
elapsed_time = end_time - start_time
elapsed_time = timedelta(seconds=elapsed_time)
print("Elapsed time:", elapsed_time)

#Combination 1: (1, 2, 3, 4, 5, 6)
#Combination 13983816: (44, 45, 46, 47, 48, 49)
#Elapsed time: 0:03:33.373467

Answered By: labetao

Python – all lottery combinations – no duplicates, in order

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