How to use youtube-dl from a python program?
Question:
I would like to access the result of the following shell command,
youtube-dl -g "www.youtube.com/..."
to print its output direct url to a file, from within a python program. This is what I have tried:
import youtube-dl
fromurl="www.youtube.com/..."
geturl=youtube-dl.magiclyextracturlfromurl(fromurl)
Is that possible?
I tried to understand the mechanism in the source but got lost: youtube_dl/__init__.py, youtube_dl/youtube_DL.py, info_extractors …
Answers:
If youtube-dl is a terminal program, you can use the subprocess module to access the data you want.
Check out this link for more details: Calling an external command in Python
It’s not difficult and actually documented:
import youtube_dl
ydl = youtube_dl.YoutubeDL({'outtmpl': '%(id)s.%(ext)s'})
with ydl:
result = ydl.extract_info(
'http://www.youtube.com/watch?v=BaW_jenozKc',
download=False # We just want to extract the info
)
if 'entries' in result:
# Can be a playlist or a list of videos
video = result['entries'][0]
else:
# Just a video
video = result
print(video)
video_url = video['url']
print(video_url)
Here is a way.
We set-up options’ string, in a list, just as we set-up command line arguments. In this case opts=['-g', 'videoID']. Then, invoke youtube_dl.main(opts). In this way, we write our custom .py module, import youtube_dl and then invoke the main() function.
I would like this
from subprocess import call
command = "youtube-dl https://www.youtube.com/watch?v=NG3WygJmiVs -c"
call(command.split(), shell=False)
For simple code,
may be i think
import os
os.system('youtube-dl [OPTIONS] URL [URL...]')
Above is just running command line inside python.
Other is mentioned in the documentation Using youtube-dl on python
Here is the way
from __future__ import unicode_literals
import youtube_dl
ydl_opts = {}
with youtube_dl.YoutubeDL(ydl_opts) as ydl:
ydl.download(['https://www.youtube.com/watch?v=BaW_jenozKc'])
Usage: python3 AudioFromYtVideo.py link outputName
import os
from sys import argv
try:
if argv[1] and argv[2]:
pass
except:
print("Input: python3 [programName] [url] [outputName]")
os.system('youtube-dl -x --audio-format mp3 -o '+argv[2]+' '+argv[1])
from __future__ import unicode_literals
import youtube_dl
ydl_opts = {}
with youtube_dl.YoutubeDL(ydl_opts) as ydl:
ydl.download(['Your youtube url'])
You can use ‘format’, ‘continue’, ‘outtmpl’ in ydl_opts
As example;
ydl_opts= {
'format': '22',
'continue': True,
'outtmpl': '%(uploader)s - %(title)s.%(ext)s',
'progress_hooks': [my_hook],
}
def my_hook(d):
if d['status'] == 'downloading':
print('Downloading video!')
if d['status'] == 'finished':
print('Downloaded!')
When you need to stop playlist downloading, Just add this code into ydl_opts.
'noplaylist': True;
I would like to access the result of the following shell command,
youtube-dl -g "www.youtube.com/..."
to print its output direct url to a file, from within a python program. This is what I have tried:
import youtube-dl
fromurl="www.youtube.com/..."
geturl=youtube-dl.magiclyextracturlfromurl(fromurl)
Is that possible?
I tried to understand the mechanism in the source but got lost: youtube_dl/__init__.py, youtube_dl/youtube_DL.py, info_extractors …
If youtube-dl is a terminal program, you can use the subprocess module to access the data you want.
Check out this link for more details: Calling an external command in Python
It’s not difficult and actually documented:
import youtube_dl
ydl = youtube_dl.YoutubeDL({'outtmpl': '%(id)s.%(ext)s'})
with ydl:
result = ydl.extract_info(
'http://www.youtube.com/watch?v=BaW_jenozKc',
download=False # We just want to extract the info
)
if 'entries' in result:
# Can be a playlist or a list of videos
video = result['entries'][0]
else:
# Just a video
video = result
print(video)
video_url = video['url']
print(video_url)
Here is a way.
We set-up options’ string, in a list, just as we set-up command line arguments. In this case opts=['-g', 'videoID']. Then, invoke youtube_dl.main(opts). In this way, we write our custom .py module, import youtube_dl and then invoke the main() function.
I would like this
from subprocess import call
command = "youtube-dl https://www.youtube.com/watch?v=NG3WygJmiVs -c"
call(command.split(), shell=False)
For simple code,
may be i think
import os
os.system('youtube-dl [OPTIONS] URL [URL...]')
Above is just running command line inside python.
Other is mentioned in the documentation Using youtube-dl on python
Here is the way
from __future__ import unicode_literals
import youtube_dl
ydl_opts = {}
with youtube_dl.YoutubeDL(ydl_opts) as ydl:
ydl.download(['https://www.youtube.com/watch?v=BaW_jenozKc'])
Usage: python3 AudioFromYtVideo.py link outputName
import os
from sys import argv
try:
if argv[1] and argv[2]:
pass
except:
print("Input: python3 [programName] [url] [outputName]")
os.system('youtube-dl -x --audio-format mp3 -o '+argv[2]+' '+argv[1])
from __future__ import unicode_literals
import youtube_dl
ydl_opts = {}
with youtube_dl.YoutubeDL(ydl_opts) as ydl:
ydl.download(['Your youtube url'])
You can use ‘format’, ‘continue’, ‘outtmpl’ in ydl_opts
As example;
ydl_opts= {
'format': '22',
'continue': True,
'outtmpl': '%(uploader)s - %(title)s.%(ext)s',
'progress_hooks': [my_hook],
}
def my_hook(d):
if d['status'] == 'downloading':
print('Downloading video!')
if d['status'] == 'finished':
print('Downloaded!')
When you need to stop playlist downloading, Just add this code into ydl_opts.
'noplaylist': True;