Add numpy array as column to Pandas data frame

Question

I have a Pandas data frame object of shape (X,Y) that looks like this:

[[1, 2, 3],
[4, 5, 6],
[7, 8, 9]]

and a numpy sparse matrix (CSC) of shape (X,Z) that looks something like this

[[0, 1, 0],
[0, 0, 1],
[1, 0, 0]]

How can I add the content from the matrix to the data frame in a new named column such that the data frame will end up like this:

[[1, 2, 3, [0, 1, 0]],
[4, 5, 6, [0, 0, 1]],
[7, 8, 9, [1, 0, 0]]]

Notice the data frame now has shape (X, Y+1) and rows from the matrix are elements in the data frame.

Asked By: Mihai Damian

||

Source

Answer 1

import numpy as np
import pandas as pd
import scipy.sparse as sparse

df = pd.DataFrame(np.arange(1,10).reshape(3,3))
arr = sparse.coo_matrix(([1,1,1], ([0,1,2], [1,2,0])), shape=(3,3))
df['newcol'] = arr.toarray().tolist()
print(df)

yields

   0  1  2     newcol
0  1  2  3  [0, 1, 0]
1  4  5  6  [0, 0, 1]
2  7  8  9  [1, 0, 0]

Answered By: unutbu

Answer 2

Consider using a higher dimensional datastructure (a Panel), rather than storing an array in your column:

In [11]: p = pd.Panel({'df': df, 'csc': csc})

In [12]: p.df
Out[12]: 
   0  1  2
0  1  2  3
1  4  5  6
2  7  8  9

In [13]: p.csc
Out[13]: 
   0  1  2
0  0  1  0
1  0  0  1
2  1  0  0

Look at cross-sections etc, etc, etc.

In [14]: p.xs(0)
Out[14]: 
   csc  df
0    0   1
1    1   2
2    0   3

See the docs for more on Panels.

Answered By: Andy Hayden

Answer 3

Here is other example:

import numpy as np
import pandas as pd

""" This just creates a list of touples, and each element of the touple is an array"""
a = [ (np.random.randint(1,10,10), np.array([0,1,2,3,4,5,6,7,8,9]))  for i in 
range(0,10) ]

""" Panda DataFrame will allocate each of the arrays , contained as a touple 
element , as column"""
df = pd.DataFrame(data =a,columns=['random_num','sequential_num'])

The secret in general is to allocate the data in the form a = [ (array_11, array_12,…,array_1n),…,(array_m1,array_m2,…,array_mn) ] and panda DataFrame will order the data in n columns of arrays. Of course , arrays of arrays could be used instead of touples, in that case the form would be :
a = [ [array_11, array_12,…,array_1n],…,[array_m1,array_m2,…,array_mn] ]

This is the output if you print(df) from the code above:

                       random_num                  sequential_num
0  [7, 9, 2, 2, 5, 3, 5, 3, 1, 4]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
1  [8, 7, 9, 8, 1, 2, 2, 6, 6, 3]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
2  [3, 4, 1, 2, 2, 1, 4, 2, 6, 1]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
3  [3, 1, 1, 1, 6, 2, 8, 6, 7, 9]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
4  [4, 2, 8, 5, 4, 1, 2, 2, 3, 3]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
5  [3, 2, 7, 4, 1, 5, 1, 4, 6, 3]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
6  [5, 7, 3, 9, 7, 8, 4, 1, 3, 1]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
7  [7, 4, 7, 6, 2, 6, 3, 2, 5, 6]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
8  [3, 1, 6, 3, 2, 1, 5, 2, 2, 9]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
9  [7, 2, 3, 9, 5, 5, 8, 6, 9, 8]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

Other variation of the example above:

b = [ (i,"text",[14, 5,], np.array([0,1,2,3,4,5,6,7,8,9]))  for i in 
range(0,10) ]
df = pd.DataFrame(data=b,columns=['Number','Text','2Elemnt_array','10Element_array'])

Output of df:

   Number  Text 2Elemnt_array                 10Element_array
0       0  text       [14, 5]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
1       1  text       [14, 5]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
2       2  text       [14, 5]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
3       3  text       [14, 5]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
4       4  text       [14, 5]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
5       5  text       [14, 5]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
6       6  text       [14, 5]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
7       7  text       [14, 5]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
8       8  text       [14, 5]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
9       9  text       [14, 5]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

If you want to add other columns of arrays, then:

df['3Element_array']=[([1,2,3]),([1,2,3]),([1,2,3]),([1,2,3]),([1,2,3]),([1,2,3]),([1,2,3]),([1,2,3]),([1,2,3]),([1,2,3])]

The final output of df will be:

   Number  Text 2Elemnt_array                 10Element_array 3Element_array
0       0  text       [14, 5]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]      [1, 2, 3]
1       1  text       [14, 5]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]      [1, 2, 3]
2       2  text       [14, 5]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]      [1, 2, 3]
3       3  text       [14, 5]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]      [1, 2, 3]
4       4  text       [14, 5]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]      [1, 2, 3]
5       5  text       [14, 5]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]      [1, 2, 3]
6       6  text       [14, 5]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]      [1, 2, 3]
7       7  text       [14, 5]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]      [1, 2, 3]
8       8  text       [14, 5]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]      [1, 2, 3]
9       9  text       [14, 5]  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]      [1, 2, 3]

Answered By: Jorge Vilchis

Answer 4

You can add and retrieve a numpy array from dataframe using this:

import numpy as np
import pandas as pd

df = pd.DataFrame({'b':range(10)}) # target dataframe
a = np.random.normal(size=(10,2)) # numpy array
df['a']=a.tolist() # save array
np.array(df['a'].tolist()) # retrieve array

This builds on the previous answer that confused me because of the sparse part and this works well for a non-sparse numpy arrray.

Answered By: citynorman

Answer 5

df = pd.DataFrame(np.arange(1,10).reshape(3,3))
df['newcol'] = pd.Series(your_2d_numpy_array)

Answered By: Max Bileschi

Add numpy array as column to Pandas data frame

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