Numpy Array Get row index searching by a row

Question

I am new to numpy and I am implementing clustering with random forest in python. My question is:

How could I find the index of the exact row in an array? For example

[[ 0.  5.  2.]
 [ 0.  0.  3.]
 [ 0.  0.  0.]]

and I look for [0. 0. 3.] and get as result 1(the index of the second row).

Any suggestion? Follows the code (not working…)

    for index, element in enumerate(leaf_node.x):
        for index_second_element, element_two in enumerate(leaf_node.x):
            if (index <= index_second_element):
                index_row = np.where(X == element)
                index_column = np.where(X == element_two)
                self.similarity_matrix[index_row][index_column] += 1

Asked By: user2801023

||

Source

Answer 1

Why not simply do something like this?

>>> a
array([[ 0.,  5.,  2.],
       [ 0.,  0.,  3.],
       [ 0.,  0.,  0.]])
>>> b
array([ 0.,  0.,  3.])

>>> a==b
array([[ True, False, False],
       [ True,  True,  True],
       [ True,  True, False]], dtype=bool)

>>> np.all(a==b,axis=1)
array([False,  True, False], dtype=bool)

>>> np.where(np.all(a==b,axis=1))
(array([1]),)

Answered By: Daniel

Answer 2

a=[[ 0.,5.,  2.],
[ 0. , 0.,  3.],
[ 0.,  0.,  0.]]

for i in enumerate(a):
    if i[1]==[ 0. , 0.,  3.]:
        print(i[0])

Answered By: Jorg from Jorgia

Numpy Array Get row index searching by a row

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