How do you sort a list in Jinja2?

Question:

I am trying to do this:

 {% for movie in movie_list | sort(movie.rating) %}

But that’s not right…the documentation is vague…how do you do this in Jinja2?

Asked By: Nick Perkins

||

Answers:

Usually we sort the list before giving it to Jinja2. There’s no way to specify a key in Jinja’s sort filter.

However, you can always try {% for movie in movie_list|sort %}. That’s the syntax. You don’t get to provide any sort of key information for the sorting.

You can also try and write a custom filter for this. Seems silly when you can sort before giving the data to Jinja2.

If movie_list is a list of objects, then you can define the various comparison methods (__lt__, __gt__, etc.) for the class of those objects.

If movie_list is a list of tuples or lists, the rating must be first. Or you’ll have to do the sorting outside Jinja2.

If movie_list is a list of dictionaries, then you can use dictsort, which does accept a key specification for the sorting. Read this: http://jinja.pocoo.org/2/documentation/templates#dictsort for an example.

Answered By: S.Lott

As of version 2.6, Jinja2’s built-in sort filter allows you to specify an attribute to sort by:

{% for movie in movie_list|sort(attribute='rating') %}

See http://jinja.pocoo.org/docs/templates/#sort

Answered By: Steve S

If you want to sort in ascending order

{% for movie in movie_list|sort(attribute='rating') %}

If you want to sort in descending order

{% for movie in movie_list|sort(attribute='rating', reverse = True) %}
Answered By: SumanKalyan
Categories: questions Tags: , ,
Answers are sorted by their score. The answer accepted by the question owner as the best is marked with
at the top-right corner.