Simplest way of checking for string that contains a string in list?

Question

I find myself repeatedly writing the same chunk of code:

def stringInList(str, list):
    retVal = False
    for item in list:
        if str in item:
            retVal = True
    return retVal

Is there any way I can write this function quicker/with less code?
I usually use this in an if statement, like this:

if stringInList(str, list):
    print 'string was found!'

Asked By: fredrik

||

Source

Answer 1

Yes, use any():

if any(s in item for item in L):
    print 'string was found!'

As the docs mention, this is pretty much equivalent to your function, but any() can take generator expressions instead of just a string and a list, and any() short-circuits. Once s in item is True, the function breaks (you can simply do this with your function if you just change retVal = True to return True. Remember that functions break when it returns a value).

You should avoid naming strings str and lists list. That will override the built-in types.

Answered By: TerryA

Simplest way of checking for string that contains a string in list?

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