What does "TypeError: 'float' object cannot be interpreted as an integer" mean when using range?

Question

I don’t understand why I can’t use my variable c.

code:

from turtle import *

speed(0)
hideturtle()
c = 450

def grid(x,y,a):
    seth(0)
    pu()
    goto(x,y)
    pd()
    for i in range(4):
        forward(a)
        rt(90)
    for i in range(c/10):
        seth(0)
        forward(10)
        rt(90)
        forward(c)
        backward(c)
    for i in range(c/10):
        seth(0)
        rt(90)
        forward(10)
        rt(90)
        forward(c)
        backward(c)
    pu()
    goto(a+10,0)
    write("x")
    goto(0,a+10)
    write("y")
    pd()

grid(0,0,c)
grid(-c,0,c)
grid(-c,c,c)
grid(0,c,c)

I get the following error message:

Traceback (most recent call last):
  File "C:UsersnickDesktopgridv2.py", line 35, in <module>
    grid(0,0,c)
  File "C:UsersnickDesktopgridv2.py", line 15, in grid
    for i in range(c/10):
TypeError: 'float' object cannot be interpreted as an integer

Asked By: remorath

||

Source

Answer 1

range() can only work with integers, but dividing with the / operator always results in a float value:

>>> 450 / 10
45.0
>>> range(450 / 10)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: 'float' object cannot be interpreted as an integer

Make the value an integer again:

for i in range(int(c / 10)):

or use the // floor division operator:

for i in range(c // 10):

Answered By: Martijn Pieters

Answer 2

In:

for i in range(c/10):

You’re creating a float as a result – to fix this use the int division operator:

for i in range(c // 10):

Answered By: Jon Clements

Answer 3

As shown below, range only supports integers:

>>> range(15.0)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: range() integer end argument expected, got float.
>>> range(15)
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14]
>>>

However, c/10 is a float because / always returns a float.

Before you put it in range, you need to make c/10 an integer. This can be done by putting it in int:

range(int(c/10))

or by using //, which returns an integer:

range(c//10)

Answered By: user2555451

Answer 4

It is also possible to fix this with np.arange() which works for float numbers, instead of range:

import numpy as np
for i in np.arange(c/10):

Answered By: Andreas

What does "TypeError: 'float' object cannot be interpreted as an integer" mean when using range?

Question:

Answers: