How to split a byte string into separate bytes in python
Question:
Ok so I’ve been using python to try create a waveform image and I’m getting the raw data from the .wav file using song = wave.open() and song.readframes(1), which returns :
b'x00x00x00x00x00x00'
What I want to know is how I split this into three separate bytes, e.g. b'x00x00', b'x00x00', b'x00x00' because each frame is 3 bytes wide so I need the value of each individual byte to be able to make a wave form. I believe that’s how I need to do it anyway.
Answers:
You can use slicing on byte objects:
>>> value = b'x00x01x00x02x00x03'
>>> value[:2]
b'x00x01'
>>> value[2:4]
b'x00x02'
>>> value[-2:]
b'x00x03'
When handling these frames, however, you probably also want to know about memoryview() objects; these let you interpret the bytes as C datatypes without any extra work on your part, simply by casting a ‘view’ on the underlying bytes:
>>> mv = memoryview(value).cast('H')
>>> mv[0], mv[1], mv[2]
256, 512, 768
The mv object is now a memory view interpreting every 2 bytes as an unsigned short; so it now has length 3 and each index is an integer value, based on the underlying bytes.
Here is a way that you can split the bytes into a list:
data = b'x00x00x00x00x00x00'
info = [data[i:i+2] for i in range(0, len(data), 2)]
print info
gives the result:
['x00x00', 'x00x00', 'x00x00']
You are actually asking about serialization/deserialization. Use struct.pack and struct.unpack (https://docs.python.org/3/library/struct.html). This gives you nice primitives to do both unpacking and things like endian swapping. For example:
import struct
struct.unpack("<H",b"x00x01") # unpacks 2 byte little endian unsigned int
struct.unpack(">l",b"x00x01x02x03") # unpacks 4 byte big endian signed int
Note that your example splits 2 byte words, not bytes.
Since this question is also coming up in searches about splitting binary strings:
value = b'x00x01x00x02x00x03'
split = [value[i] for i in range (0, len(value))]
# now you can modify, for example:
split[1] = 5
# put it back together
joined = bytes(split)
Ok so I’ve been using python to try create a waveform image and I’m getting the raw data from the .wav file using song = wave.open() and song.readframes(1), which returns :
b'x00x00x00x00x00x00'
What I want to know is how I split this into three separate bytes, e.g. b'x00x00', b'x00x00', b'x00x00' because each frame is 3 bytes wide so I need the value of each individual byte to be able to make a wave form. I believe that’s how I need to do it anyway.
You can use slicing on byte objects:
>>> value = b'x00x01x00x02x00x03'
>>> value[:2]
b'x00x01'
>>> value[2:4]
b'x00x02'
>>> value[-2:]
b'x00x03'
When handling these frames, however, you probably also want to know about memoryview() objects; these let you interpret the bytes as C datatypes without any extra work on your part, simply by casting a ‘view’ on the underlying bytes:
>>> mv = memoryview(value).cast('H')
>>> mv[0], mv[1], mv[2]
256, 512, 768
The mv object is now a memory view interpreting every 2 bytes as an unsigned short; so it now has length 3 and each index is an integer value, based on the underlying bytes.
Here is a way that you can split the bytes into a list:
data = b'x00x00x00x00x00x00'
info = [data[i:i+2] for i in range(0, len(data), 2)]
print info
gives the result:
['x00x00', 'x00x00', 'x00x00']
You are actually asking about serialization/deserialization. Use struct.pack and struct.unpack (https://docs.python.org/3/library/struct.html). This gives you nice primitives to do both unpacking and things like endian swapping. For example:
import struct
struct.unpack("<H",b"x00x01") # unpacks 2 byte little endian unsigned int
struct.unpack(">l",b"x00x01x02x03") # unpacks 4 byte big endian signed int
Note that your example splits 2 byte words, not bytes.
Since this question is also coming up in searches about splitting binary strings:
value = b'x00x01x00x02x00x03'
split = [value[i] for i in range (0, len(value))]
# now you can modify, for example:
split[1] = 5
# put it back together
joined = bytes(split)