Convert timedelta to floating-point


I got a timedelta object from the subtraction of two datetimes. I need this value as floating point for further calculations.
All that I’ve found enables the calculation with floating-points, but the result
is still a timedelta object.

time_d = datetime_1 - datetime_2
time_d_float = float(time_d)

does not work.

Asked By: fidelitas



You could use the total_seconds method:

time_d_float = time_d.total_seconds()
Answered By: unutbu

In Python 3.2 or higher, you can divide two timedeltas to give a float. This is useful if you need the value to be in units other than seconds.

time_d_min = time_d / datetime.timedelta(minutes=1)
time_d_ms  = time_d / datetime.timedelta(milliseconds=1)
Answered By: dan04

I had the same problem before and I used timedelta.total_seconds to get Estimated duration into seconds with float and it works.
I hope this works for you.

from datetime import timedelta,datetime

time_d = datetime_1 - datetime_2

Answered By: Faith

If you needed the number of days as a floating number you can use timedelta’s days attribute

time_d = datetime_1 - datetime_2
number_of_days = float(time_d.days)
Answered By: RoachLord

You could use numpy to solve that:

import pandas as pd
import numpy as np

time_d = datetime_1 - datetime_2

#for a single value
number_of_days =pd.DataFrame([time_d]).apply(np.float32)

#for a Dataframe
number_of_days = time_d.apply(np.float32)

Hope it is helpful!

Answered By: Monique Marins
from datetime import timedelta,datetime
x1= timedelta(seconds=40, minutes=40, hours=5)
x2= timedelta( seconds=50, minutes=20, hours=4)
x5 = x3.total_seconds()

# if you are working with Dataframe then use loop (* for-loop).
Answered By: Mrityunjaya Chauhan