Finding Signed Angle Between Vectors
Question:
How would you find the signed angle theta from vector a to b?
And yes, I know that theta = arccos((a.b)/(|a||b|)).
However, this does not contain a sign (i.e. it doesn’t distinguish between a clockwise or counterclockwise rotation).
I need something that can tell me the minimum angle to rotate from a to b. A positive sign indicates a rotation from +x-axis towards +y-axis. Conversely, a negative sign indicates a rotation from +x-axis towards -y-axis.
assert angle((1,0),(0,1)) == pi/2.
assert angle((0,1),(1,0)) == -pi/2.
Answers:
If you have an atan2() function in your math library of choice:
signed_angle = atan2(b.y,b.x) - atan2(a.y,a.x)
What you want to use is often called the “perp dot product”, that is, find the vector perpendicular to one of the vectors, and then find the dot product with the other vector.
if(a.x*b.y - a.y*b.x < 0)
angle = -angle;
You can also do this:
angle = atan2( a.x*b.y - a.y*b.x, a.x*b.x + a.y*b.y );
How would you find the signed angle theta from vector a to b?
And yes, I know that theta = arccos((a.b)/(|a||b|)).
However, this does not contain a sign (i.e. it doesn’t distinguish between a clockwise or counterclockwise rotation).
I need something that can tell me the minimum angle to rotate from a to b. A positive sign indicates a rotation from +x-axis towards +y-axis. Conversely, a negative sign indicates a rotation from +x-axis towards -y-axis.
assert angle((1,0),(0,1)) == pi/2.
assert angle((0,1),(1,0)) == -pi/2.
If you have an atan2() function in your math library of choice:
signed_angle = atan2(b.y,b.x) - atan2(a.y,a.x)
What you want to use is often called the “perp dot product”, that is, find the vector perpendicular to one of the vectors, and then find the dot product with the other vector.
if(a.x*b.y - a.y*b.x < 0)
angle = -angle;
You can also do this:
angle = atan2( a.x*b.y - a.y*b.x, a.x*b.x + a.y*b.y );