Converting epoch time with milliseconds to datetime

Question

I have used a ruby script to convert iso time stamp to epoch, the files that I am parsing has following time stamp structure:

2009-03-08T00:27:31.807

Since I want to keep milliseconds I used following ruby code to convert it to epoch time:

irb(main):010:0> DateTime.parse('2009-03-08T00:27:31.807').strftime("%Q")
=> "1236472051807"

But In python I tried following:

import time 
time.strftime('%Y-%m-%d %H:%M:%S', time.gmtime(1236472051807))

But I don’t get the original time date time back,

>>> time.strftime('%Y-%m-%d %H:%M:%S', time.gmtime(1236472051807))
'41152-03-29 02:50:07'
>>>

I wonder is it related to how I am formatting?

Asked By: add-semi-colons

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Source

Answer 1

those are miliseconds, just divide them by 1000, since gmtime expects seconds …

time.strftime('%Y-%m-%d %H:%M:%S', time.gmtime(1236472051807/1000.0))

Answered By: Joran Beasley

Answer 2

Use datetime.datetime.fromtimestamp:

>>> import datetime
>>> s = 1236472051807 / 1000.0
>>> datetime.datetime.fromtimestamp(s).strftime('%Y-%m-%d %H:%M:%S.%f')
'2009-03-08 09:27:31.807000'

%f directive is only supported by datetime.datetime.strftime, not by time.strftime.

UPDATE Alternative using %, str.format:

>>> import time
>>> s, ms = divmod(1236472051807, 1000)  # (1236472051, 807)
>>> '%s.%03d' % (time.strftime('%Y-%m-%d %H:%M:%S', time.gmtime(s)), ms)
'2009-03-08 00:27:31.807'
>>> '{}.{:03d}'.format(time.strftime('%Y-%m-%d %H:%M:%S', time.gmtime(s)), ms)
'2009-03-08 00:27:31.807'

Answered By: falsetru

Answer 3

I’m a pendulum fan… so…

import pendulum
pendulum.from_timestamp(1236472051807/1000.0,tz='America/Toronto')

outputs:

DateTime(2019, 12, 20, 10, 55, 10, tzinfo=Timezone('America/Toronto'))

For all the searches looking for internalDate for the Gmail API… the above is what works for me and is more accurate than the Date header.

Answered By: rjmoggach

Converting epoch time with milliseconds to datetime

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