How to create a new database using python and sqlite3
Question:
import sqlite3
conn = sqlite3.connect(r"D:aaa.db")
Is there a way to automatically create the db file if it doesn’t already exist when I connect to it?
Answers:
The code you give does create 'D:\aaa.db' if it doesn’t exist.
Pretty sure .connect will create the file if it doesn’t exist.
If it isn’t created automatically, make sure that you have the directory permissions correct
.connect should create a new database file on the fly, given sub-directories do exist, and you have adequate permissioning.
import sqlite3
conn=sqlite3.connect('xx.db')
print "Database created and opened succesfully"
As it was already mentioned, your code should work if you have permissions to write for this path. However, it is important that directory must exist. If you make call for non-existing folder:
conn = sqlite3.connect(r"D:Some new non-existing folderaaa.db")
It will not work, you will have
sqlite3.OperationalError: unable to open database file.
The same is for relative paths:
1) conn = sqlite3.connect(r"aaa.db")
2) conn = sqlite3.connect(r"Some new folderaaa.db")
First will always work, because you are working in already existing directory and second will not work if you do not create te folder beforehand.
import sqlite3
conn = sqlite3.connect(r"D:aaa.db")
Is there a way to automatically create the db file if it doesn’t already exist when I connect to it?
The code you give does create 'D:\aaa.db' if it doesn’t exist.
Pretty sure .connect will create the file if it doesn’t exist.
If it isn’t created automatically, make sure that you have the directory permissions correct
.connect should create a new database file on the fly, given sub-directories do exist, and you have adequate permissioning.
import sqlite3
conn=sqlite3.connect('xx.db')
print "Database created and opened succesfully"
As it was already mentioned, your code should work if you have permissions to write for this path. However, it is important that directory must exist. If you make call for non-existing folder:
conn = sqlite3.connect(r"D:Some new non-existing folderaaa.db")
It will not work, you will have
sqlite3.OperationalError: unable to open database file.
The same is for relative paths:
1) conn = sqlite3.connect(r"aaa.db")
2) conn = sqlite3.connect(r"Some new folderaaa.db")
First will always work, because you are working in already existing directory and second will not work if you do not create te folder beforehand.