Reading Excel File using Python, how do I get the values of a specific column with indicated column name?

So the key parts are to grab the header ( col_names = s.row(0) ) and when iterating through the rows, to skip the first row which isn’t needed for row in range(1, s.nrows) – done by using range from 1 onwards (not the implicit 0). You then use zip to step through the rows holding ‘name’ as the header of the column.

from xlrd import open_workbook

wb = open_workbook('Book2.xls')
values = []
for s in wb.sheets():
    #print 'Sheet:',s.name
    for row in range(1, s.nrows):
        col_names = s.row(0)
        col_value = []
        for name, col in zip(col_names, range(s.ncols)):
            value  = (s.cell(row,col).value)
            try : value = str(int(value))
            except : pass
            col_value.append((name.value, value))
        values.append(col_value)
print values

The approach I took reads the header information from the first row to determine the indexes of the columns of interest.

You mentioned in the question that you also want the values output to a string. I dynamically build a format string for the output from the FORMAT column list. Rows are appended to the values string separated by a new line char.

The output column order is determined by the order of the column names in the FORMAT list.

In my code below the case of the column name in the FORMAT list is important. In the question above you’ve got ‘Pincode’ in your FORMAT list, but ‘PinCode’ in your excel. This wouldn’t work below, it would need to be ‘PinCode’.

from xlrd import open_workbook
wb = open_workbook('sample.xls')

FORMAT = ['Arm_id', 'DSPName', 'PinCode']
values = ""

for s in wb.sheets():
    headerRow = s.row(0)
    columnIndex = [x for y in FORMAT for x in range(len(headerRow)) if y == firstRow[x].value]
    formatString = ("%s,"*len(columnIndex))[0:-1] + "n"

    for row in range(1,s.nrows):
        currentRow = s.row(row)
        currentRowValues = [currentRow[x].value for x in columnIndex]
        values += formatString % tuple(currentRowValues)

print values

For the sample input you gave above this code outputs:

>>> 1.0,JaVAS,282001.0
2.0,JaVAS,282002.0
3.0,JaVAS,282003.0

And because I’m a python noob, props be to:
this answer,
this answer,
this question,
this question
and this answer.

A somewhat late answer, but with pandas, it is possible to get directly a column of an excel file:

import pandas

df = pandas.read_excel('sample.xls')
#print the column names
print df.columns
#get the values for a given column
values = df['Arm_id'].values
#get a data frame with selected columns
FORMAT = ['Arm_id', 'DSPName', 'Pincode']
df_selected = df[FORMAT]

Make sure you have installed xlrd and pandas:

pip install pandas xlrd

By using pandas we can read excel easily.

import pandas as pd 
from pandas import ExcelWriter
from pandas import ExcelFile 

DataF=pd.read_excel("Test.xlsx",sheet_name='Sheet1')

print("Column headings:")
print(DataF.columns)

Test at :https://repl.it
Reference: https://pythonspot.com/read-excel-with-pandas/

Although I almost always just use pandas for this, my current little tool is being packaged into an executable and including pandas is overkill. So I created a version of poida‘s solution that resulted in a list of named tuples. His code with this change would look like this:

from xlrd import open_workbook
from collections import namedtuple
from pprint import pprint

wb = open_workbook('sample.xls')

FORMAT = ['Arm_id', 'DSPName', 'PinCode']
OneRow = namedtuple('OneRow', ' '.join(FORMAT))
all_rows = []

for s in wb.sheets():
    headerRow = s.row(0)
    columnIndex = [x for y in FORMAT for x in range(len(headerRow)) if y == headerRow[x].value]

    for row in range(1,s.nrows):
        currentRow = s.row(row)
        currentRowValues = [currentRow[x].value for x in columnIndex]
        all_rows.append(OneRow(*currentRowValues))

pprint(all_rows)

Here is the code to read an excel file and and print all the cells present in column 1 (except the first cell i.e the header):

import xlrd

file_location="C:pythonprogxxx.xlsv"
workbook=xlrd.open_workbook(file_location)
sheet=workbook.sheet_by_index(0)
print(sheet.cell_value(0,0))

for row in range(1,sheet.nrows):
     print(sheet.cell_value(row,0))

I have read using openpyxl library,

import openpyxl
from pathlib import Path

xlsx_file = Path('C:\Users\Amit\Desktop\ReadExcel', 'ReadData.xlsx')
wb_obj = openpyxl.load_workbook(xlsx_file) 

# Read the active sheet:
sheet = wb_obj.active

for i in range(sheet.max_column):
    print(f'i = {i}')
    for row in sheet.iter_rows():
        print(row[i].value)