What is the pythonic way to unpack tuples as function arguments?

Question

This is ugly. What’s a more Pythonic way to do it?

import datetime

t= (2010, 10, 2, 11, 4, 0, 2, 41, 0)
dt = datetime.datetime(t[0], t[1], t[2], t[3], t[4], t[5], t[6])

Asked By: user132262

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Answer 1

Generally, you can use the func(*tuple) syntax. You can even pass a part of the tuple, which seems like what you’re trying to do here:

t = (2010, 10, 2, 11, 4, 0, 2, 41, 0)
dt = datetime.datetime(*t[0:7])

This is called unpacking a tuple, and can be used for other iterables (such as lists) too. Here’s another example (from the Python tutorial):

>>> range(3, 6)             # normal call with separate arguments
[3, 4, 5]
>>> args = [3, 6]
>>> range(*args)            # call with arguments unpacked from a list
[3, 4, 5]

Answered By: Eli Bendersky

Answer 2

Refer https://docs.python.org/2/tutorial/controlflow.html#unpacking-argument-lists

 dt = datetime.datetime(*t[:7])

Answered By: Charles Beattie

What is the pythonic way to unpack tuples as function arguments?

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