getting sheet names from openpyxl

Question

I have a moderately large xlsx file (around 14 MB) and OpenOffice hangs trying to open it. I was trying to use openpyxl to read the content, following this tutorial. The code snippet is as follows:

 from openpyxl import load_workbook
 wb = load_workbook(filename = 'large_file.xlsx', use_iterators = True)
 ws = wb.get_sheet_by_name(name = 'big_data')

The problem is, I don’t know the sheet name, and Sheet1/Sheet2.. etc. didn’t work (returned NoneType object). I could not find a documentation telling me How to get the sheet names for an xlsx files using openpyxl. Can anyone help me?

Asked By: rivu

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Source

Answer 1

Use the sheetnames property:

sheetnames

Returns the list of the names of worksheets in this workbook.

Names are returned in the worksheets order.

Type: list of strings

print (wb.sheetnames)

You can also get worksheet objects from wb.worksheets:

ws = wb.worksheets[0]

Answered By: alecxe

Answer 2

As mentioned the earlier answer
you can get the list of sheet names
by using the ws.sheetnames

But if you know the sheet names you can get that worksheet object by

ws.get_sheet_by_name("YOUR_SHEET_NAME")

Another way of doing this is as mentioned in earlier answer

ws['YOUR_SHEET_NAME']

Answered By: Kamaraj

Answer 3

python 3.x
for get sheet name you must use attribute

g_sheet=wb.sheetnames

return by list

for i in g_sheet:
    print(i)

**shoose any name **

ws=wb[g_sheet[0]]

or ws=wb[any name]
suppose name sheet is paster

ws=wb["paster"]

Answered By: ismail

Answer 4

As a complement to the other answers, for a particular worksheet, you can also use cf documentation in the constructor parameters:

ws.title

Answered By: lalebarde

Answer 5

for worksheet in workbook:
    print(worksheet.name)

Answered By: lulu

getting sheet names from openpyxl

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