How to create multiple lists?

Question:

I’m trying to create multiple lists like the following:

l1 = []  
l2 = []  
..  
ln = []  

Is there any way to do that?

Asked By: Sathish Bowatta

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Answers:

Create a list of lists:

lists = []
n = 20
for i in range(n):
    lists.append([])

print lists[0] # Prints []
print lists[19] # Prints []
Answered By: huu

What you can do is use a dictionary:

>>> obj = {}
>>> for i in range(1, 21):
...     obj['l'+str(i)] = []
... 
>>> obj
{'l18': [], 'l19': [], 'l20': [], 'l14': [], 'l15': [], 'l16': [], 'l17': [], 'l10': [], 'l11': [], 'l12': [], 'l13': [], 'l6': [], 'l7': [], 'l4': [], 'l5': [], 'l2': [], 'l3': [], 'l1': [], 'l8': [], 'l9': []}
>>> 

You can also create a list of lists using list comprehension:

>>> obj = [[] for i in range(20)]
>>> obj
[[], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], []]
>>> 
Answered By: A.J. Uppal

You can simply use a for loop to create n lists.

for i in range(10):
a_i = [i] #Stores the corresponding value of i in each a_i list.
print(a_i)

The variable a_i changes as i increments, so it becomes a_1, a_2, a_3 … and so on.

Answered By: Akhzar Farhan

You can use dictionary comprehension:

obj = {i:[] for i in list(range(1,5))}
Answered By: Cindyleee

there is a way to do that if you want to create variables. but instead, u should use a dictionary as mentioned above. but anyway I am going to show you how to create variables as you asked.

for i in range(num_vars):
     globals()[f'ls{i}'] = []

print(ls1) # lsn should work
Answered By: Hyperx837

Just Extending Already Accepted Answer,
Using Enumerate to initiate default values in list.
Accessing list and adding values which was not mentioned.

range_list = list(range (int(input())))
obj = {}


for i, j in enumerate(range_list): # assigning default values
    obj['l'+str(i)] = [j**2]
   
print(obj['l0'])
print(type(obj['l0']))

obj['l0'] = list(range(5)) # accessing list
print(obj['l0'])

#3 asking user, how many list to be created 
#[0] default value in first list
#<class 'list'>
#[0, 1, 2, 3, 4] current value in first list

#[Program finished]
Answered By: Subham
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