Python 'long' object has no attribute 'to_bytes'?

Question

I’m trying to use a bitcoin address validator written in Python from here:

This snippet gives me trouble though:

def decode_base58(bc, length):
    n = 0
    for char in bc:
        n = n * 58 + digits58.index(char)
    return n.to_bytes(length, 'big')

I understand that n is either an int or a long, but neither has a method called to_bytes, so I don’t really understand how this code could have ever worked?

Does anybody know what’s wrong here? Am I doing something wrong, or is this code simply written wrong? All tips are welcome!

Asked By: kramer65

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Source

Answer 1

Since Python 3.2 the built-in integer types provide a to_bytes method.
https://docs.python.org/3/library/stdtypes.html#int.to_bytes

Answered By: wonce

Answer 2

Python 2.7 int and long don’t have the .to_bytes method. Python 3.2 int has the .to_bytes method.

A workaround for Python 2.x:

>>> length = 10
>>> n = 123456789
>>> ('%%0%dx' % (length << 1) % n).decode('hex')[-length:]
'x00x00x00x00x00x00x07[xcdx15'

Answered By: pts

Answer 3

The code you linked contains :

assert n.to_bytes(length, 'big') == bytes( (n >> i*8) & 0xff for i in reversed(range(length)))

which means that you can define a to_bytes function:

def to_bytes(n, length):
    return bytes( (n >> i*8) & 0xff for i in reversed(range(length)))

And use it as such:

def decode_base58(bc, length):
    n = 0
    for char in bc:
        n = n * 58 + digits58.index(char)
    return to_bytes(n, length)

Answered By: njzk2

Answer 4

This provided me th required result it was in the comments given by @martineau

''.join(chr((n >> i*8) & 0xff) for i in reversed(range(length)))

Answered By: Akshay

Python 'long' object has no attribute 'to_bytes'?

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