How can I split a module into multiple files, without breaking a backwards compatibly?

Question

Let’s say I have a model.py file that looks like this:

class Foo():
  ..

class Bar():
  ..

From other modules I’m importing the model and then using model.Foo()
whenever I want to refer to them.

import model

foo = model.Foo()

As this file is growing bigger I would like to split each class
into multiple files, but without breaking the backwards compatibility if
possible.

My idea was to break it like this:

model
├── __init__.py
├── foo.py
└── bar.py

but by doing that I will have to refer to them as model.foo.Foo().

So my question is: is it possible to split it in multiple files somehow but still referring to them as model.Foo()?

I should also be able to extend or use Foo inside Bar.

Asked By: Lipis

||

Answer 1

Sure you can, just import the classes in the __init__.py:

# in __init__.py
from model.foo import Foo
from model.bar import Bar

And then when you wish to use them you can:

>>> import model
>>> model.Bar()
<model.bar.Bar object at 0x31306d0>

or

>>> from model import Foo
>>> Foo()
<model.foo.Foo object at 0x31307d0>

Answered By: msvalkon

Question: