How to convert back-slashes to forward-slashes?
Question:
I am working in python and I need to convert this:
C:folderAfolderB to C:/folderA/folderB
I have three approaches:
dir = s.replace('\','/')
dir = os.path.normpath(s)
dir = os.path.normcase(s)
In each scenario the output has been
C:folderAfolderB
I’m not sure what I am doing wrong, any suggestions?
Answers:
Try
path = '/'.join(path.split('\'))
Your specific problem is the order and escaping of your replace arguments, should be
s.replace('\', '/')
Then there’s:
posixpath.join(*s.split('\'))
Which on a *nix platform is equivalent to:
os.path.join(*s.split('\'))
But don’t rely on that on Windows because it will prefer the platform-specific separator. Also:
Note that on Windows, since there is a current directory for each
drive, os.path.join(“c:”, “foo”) represents a path relative to the
current directory on drive C: (c:foo), not c:foo.
How about :
import ntpath
import posixpath
.
.
.
dir = posixpath.join(*ntpath.split(s))
.
.
To define the path’s variable you have to add r initially, then add the replace statement .replace('\', '/') at the end.
for example:
In>> path2 = r'C:UsersUserDocumentsProjectEm2Lph'.replace('\', '/')
In>> path2
Out>> 'C:/Users/User/Documents/Project/Em2Lph/'
This solution requires no additional libraries
I recently found this and thought worth sharing:
import os
path = "C:\tempmyFolderexample\"
newPath = path.replace(os.sep, '/')
print(newPath) # -> C:/temp/myFolder/example/
Path names are formatted differently in Windows. the solution is simple, suppose you have a path string like this:
data_file = "/Users/username/Downloads/PMLSdata/series.csv"
simply you have to change it to this: (adding r front of the path)
data_file = r"/Users/username/Downloads/PMLSdata/series.csv"
The modifier r before the string tells Python that this is a raw string. In raw strings, the backslash is interpreted literally, not as an escape character.
Sorry for being late to the party, but I wonder no one has suggested the pathlib-library.
pathlib is a module for "Object-oriented filesystem paths"
To convert from windows-style (backslash)-paths to forward-slashes (as typically for Posix-Paths) you can do so in a very verbose (AND platform-independant) fashion with pathlib:
import pathlib
pathlib.PureWindowsPath(r"C:folderAfolderB").as_posix()
>>> 'C:/folderA/folderB'
Be aware that the example uses the string-literal "r" (to avoid having "" as escape-char)
In other cases the path should be quoted properly (with double backslashes) "C:\folderA\folderB"
This can work also:
def slash_changer(directory):
if "\" in directory:
return directory.replace(os.sep, '/')
else:
return directory
print(slash_changer(os.getcwd()))
this is the perfect solution put the letter ‘r’ before the string that you want to convert to avoid all special characters likes ‘t’ and ‘f’…
like the example below:
str= r"testhhd"
print("windows path:",str.replace("\","\\"))
print("Linux path:",str.replace("\","/"))
result:
windows path: \test\hhd
Linux path: /test/hhd
I am working in python and I need to convert this:
C:folderAfolderB to C:/folderA/folderB
I have three approaches:
dir = s.replace('\','/')
dir = os.path.normpath(s)
dir = os.path.normcase(s)
In each scenario the output has been
C:folderAfolderB
I’m not sure what I am doing wrong, any suggestions?
Try
path = '/'.join(path.split('\'))
Your specific problem is the order and escaping of your replace arguments, should be
s.replace('\', '/')
Then there’s:
posixpath.join(*s.split('\'))
Which on a *nix platform is equivalent to:
os.path.join(*s.split('\'))
But don’t rely on that on Windows because it will prefer the platform-specific separator. Also:
Note that on Windows, since there is a current directory for each
drive, os.path.join(“c:”, “foo”) represents a path relative to the
current directory on drive C: (c:foo), not c:foo.
How about :
import ntpath
import posixpath
.
.
.
dir = posixpath.join(*ntpath.split(s))
.
.
To define the path’s variable you have to add r initially, then add the replace statement .replace('\', '/') at the end.
for example:
In>> path2 = r'C:UsersUserDocumentsProjectEm2Lph'.replace('\', '/')
In>> path2
Out>> 'C:/Users/User/Documents/Project/Em2Lph/'
This solution requires no additional libraries
I recently found this and thought worth sharing:
import os
path = "C:\tempmyFolderexample\"
newPath = path.replace(os.sep, '/')
print(newPath) # -> C:/temp/myFolder/example/
Path names are formatted differently in Windows. the solution is simple, suppose you have a path string like this:
data_file = "/Users/username/Downloads/PMLSdata/series.csv"
simply you have to change it to this: (adding r front of the path)
data_file = r"/Users/username/Downloads/PMLSdata/series.csv"
The modifier r before the string tells Python that this is a raw string. In raw strings, the backslash is interpreted literally, not as an escape character.
Sorry for being late to the party, but I wonder no one has suggested the pathlib-library.
pathlib is a module for "Object-oriented filesystem paths"
To convert from windows-style (backslash)-paths to forward-slashes (as typically for Posix-Paths) you can do so in a very verbose (AND platform-independant) fashion with pathlib:
import pathlib
pathlib.PureWindowsPath(r"C:folderAfolderB").as_posix()
>>> 'C:/folderA/folderB'
Be aware that the example uses the string-literal "r" (to avoid having "" as escape-char)
In other cases the path should be quoted properly (with double backslashes) "C:\folderA\folderB"
This can work also:
def slash_changer(directory):
if "\" in directory:
return directory.replace(os.sep, '/')
else:
return directory
print(slash_changer(os.getcwd()))
this is the perfect solution put the letter ‘r’ before the string that you want to convert to avoid all special characters likes ‘t’ and ‘f’…
like the example below:
str= r"testhhd"
print("windows path:",str.replace("\","\\"))
print("Linux path:",str.replace("\","/"))
result:
windows path: \test\hhd
Linux path: /test/hhd