If there are several methods in the test class, I found that the order to execute is alphabetical. But I want to customize the order of execution. How to define the execution order?
For example: testTestA will be loaded first than testTestB.
class Test(TestCase): def setUp(self): ... def testTestB(self): #test code def testTestA(self): #test code
As far as I know, there is no way to order tests other than rename them. Could you explain why you need to run test cases in the specific order? In unit testing it usually considered as bad practice since it means that your cases are not independent.
A tenet of unit-testing is that each test should be independent of all others.
If in your case the code in testTestA must come before testTestB, then you could
combine both into one test:
def testTestA_and_TestB(self): # test code from testTestA ... # test code from testTestB
or, perhaps better would be
def TestA(self): # test code def TestB(self): # test code def test_A_then_B(self): self.TestA() self.TestB()
Test class only tests those methods who name begins with a lower-case
So you can put in extra helper methods
TestB which won’t get run unless you explicitly call them.
To update on the topic (from documentation):
In order to guarantee that all
TestCasecode starts with a clean
database, the Django test runner reorders tests in the following way:
TestCasesubclasses are run first.
- Then, all other Django-based
tests (test cases based on
TransactionTestCase) are run with no particular ordering guaranteed
nor enforced among them.
- Then any other
doctests) that may alter the database without restoring it
to its original state are run.
Note: The new ordering of tests may reveal unexpected dependencies on test
case ordering. This is the case with doctests that relied on state
left in the database by a given
TransactionTestCasetest, they must be
updated to be able to run independently.