How to send an email through gmail without enabling 'insecure access'?

Question:

Google are pushing us to improve the security of script access to their gmail smtp servers. I have no problem with that. In fact I’m happy to help.

But they’re not making it easy. It’s all well and good to suggest we Upgrade to a more secure app that uses the most up to date security measures, but that doesn’t help me work out how to upgrade bits of code that look like this:

server = smtplib.SMTP("smtp.gmail.com", 587)
server.ehlo()
server.starttls()
server.login(GMAIL_USER, GMAIL_PASSWORD)
server.sendmail(FROM, TO, MESSAGE)
server.close()

Sure, I’ll go and turn on “Access for less secure apps”, but if anyone has worked out what to replace this code with, I’ll be grateful.

Asked By: John Mee

||

Answers:

Have you considered using the Gmail API? The API has security features built in and is optimized specifically for Gmail. You can find the API documentation on http://developers.google.com – for example, here’s the documentation for the Send API call:

https://developers.google.com/gmail/api/v1/reference/users/messages/send

Answered By: Amber
  protected string SendEmail(string toAddress, string subject, string body)
    {
        string result = "Message Sent Successfully..!!";

        string senderID = "...........";// use sender's email id here..
        const string senderPassword = "........."; // sender password here...

        try
        {
            SmtpClient smtp = new SmtpClient
            {
                Host = "smtp.gmail.com", // smtp server address here...
                Port = 587,
                EnableSsl = true,
                DeliveryMethod = SmtpDeliveryMethod.Network,
                Credentials = new System.Net.NetworkCredential(senderID, senderPassword),
                Timeout = 30000,

            };

            MailMessage message = new MailMessage(senderID, toAddress, subject, body);

            smtp.Send(message);
        }
        catch (Exception ex)
        {
            result = "Error sending email.!!!";
        }

        return result;
    }
Answered By: Heta

This is the original 2014 answer. See the accepted answer for something more recent.

Python3 was not supported for quite a while.

I don’t think it will be too hard to attain, as I was stumbling through converting packages without hitting anything massive: just the usual 2to3 stuff. Yet after a couple of hours I got tired of swimming upstream. At time of writing, I couldn’t find a published package for public consumption for Python 3. The python 2 experience was straight-forward (in comparison).

Navigating the Google website is half the battle

No doubt, over time, this will change. Ultimately you need to download a client_secret.json file. You can only (probably) do this setting up stuff via a web browser:

  1. You need a google account – either google apps or gmail. So, if you haven’t got one, go get one.
  2. Get yourself to the developers console
  3. Create a new project, and wait 4 or 400 seconds for that to complete.
  4. Navigate to API's and Auth -> Credentials
  5. Under OAuth select Create New Client ID
  6. Choose Installed Application as the application type and Other
  7. You should now have a button Download JSON. Do that. It’s your client_secret.json—the passwords so to speak

But wait that’s not all!

You have to give your application a "Product Name" to avoid some odd errors. (see how much I suffered to give you this 😉

  1. Navigate to API's & auth -> Consent Screen
  2. Choose your email
  3. Enter a PRODUCT NAME. It doesn’t matter what it is. "Foobar" will do fine.
  4. Save

Newsflash! Whoa. Now there’s even more!

  1. Navigate to API’s & auth -> APIs -> Gmail API
  2. Click the button Enable API

Yay. Now we can update the emailing script.

Python 2

You need to run the script interactively the first time. It will open a web browser on your machine and you’ll grant permissions (hit a button). This exercise will save a file to your computer gmail.storage which contains a reusable token.

[I had no luck transferring the token to a machine which has no graphical browser functionality—returns an HTTPError. I tried to get through it via the lynx graphical browser. That also failed because google have set the final "accept" button to "disabled"!? I’ll raise another question to jump this hurdle (more grumbling)]

First you need some libraries:

pip install --upgrade google-api-python-client
pip install --upgrade python-gflags
  • you need to change the to and from addresses
  • make sure you have the client_token.json file whereever the Storage instructions expect it
  • the directory needs to be writable so it can save the gmail.storage file

Finally some code:

import base64
import httplib2

from email.mime.text import MIMEText

from apiclient.discovery import build
from oauth2client.client import flow_from_clientsecrets
from oauth2client.file import Storage
from oauth2client.tools import run


# Path to the client_secret.json file downloaded from the Developer Console
CLIENT_SECRET_FILE = 'client_secret.json'

# Check https://developers.google.com/gmail/api/auth/scopes for all available scopes
OAUTH_SCOPE = 'https://www.googleapis.com/auth/gmail.compose'

# Location of the credentials storage file
STORAGE = Storage('gmail.storage')

# Start the OAuth flow to retrieve credentials
flow = flow_from_clientsecrets(CLIENT_SECRET_FILE, scope=OAUTH_SCOPE)
http = httplib2.Http()

# Try to retrieve credentials from storage or run the flow to generate them
credentials = STORAGE.get()
if credentials is None or credentials.invalid:
  credentials = run(flow, STORAGE, http=http)

# Authorize the httplib2.Http object with our credentials
http = credentials.authorize(http)

# Build the Gmail service from discovery
gmail_service = build('gmail', 'v1', http=http)

# create a message to send
message = MIMEText("Message goes here.")
message['to'] = "[email protected]"
message['from'] = "[email protected]"
message['subject'] = "your subject goes here"
body = {'raw': base64.b64encode(message.as_string())}

# send it
try:
  message = (gmail_service.users().messages().send(userId="me", body=body).execute())
  print('Message Id: %s' % message['id'])
  print(message)
except Exception as error:
  print('An error occurred: %s' % error)

Hopefully that gets us all started. Not as simple as the old way, but does look a lot less complicated now I can see it in the flesh.

Answered By: John Mee

It seems that John Mee’s answer is out of date.
It does not work in July, 2016.
Maybe due to the update of Gmail’s API.
I update his code (python 2) as below:

    """Send an email message from the user's account.
"""

import base64
from email.mime.audio import MIMEAudio
from email.mime.base import MIMEBase
from email.mime.image import MIMEImage
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
import mimetypes
import os

#from __future__ import print_function
import httplib2
import os

from apiclient import discovery
import oauth2client
from oauth2client import client
from oauth2client import tools

from apiclient import errors

SCOPES = 'https://www.googleapis.com/auth/gmail.compose'
CLIENT_SECRET_FILE = 'client_secret.json'
APPLICATION_NAME = 'Gmail API Python Quickstart'

try:
    import argparse
    flags = argparse.ArgumentParser(parents=[tools.argparser]).parse_args()
except ImportError:
    flags = None

def SendMessage(service, user_id, message):
  """Send an email message.

  Args:
    service: Authorized Gmail API service instance.
    user_id: User's email address. The special value "me"
    can be used to indicate the authenticated user.
    message: Message to be sent.

  Returns:
    Sent Message.
  """
  try:
    message = (service.users().messages().send(userId=user_id, body=message)
               .execute())
    print 'Message Id: %s' % message['id']
    return message
  except errors.HttpError, error:
    print 'An error occurred: %s' % error


def CreateMessage(sender, to, subject, message_text):
  """Create a message for an email.

  Args:
    sender: Email address of the sender.
    to: Email address of the receiver.
    subject: The subject of the email message.
    message_text: The text of the email message.

  Returns:
    An object containing a base64url encoded email object.
  """
  message = MIMEText(message_text)
  message['to'] = to
  message['from'] = sender
  message['subject'] = subject
  return {'raw': base64.urlsafe_b64encode(message.as_string())}


def get_credentials():
    """Gets valid user credentials from storage.

    If nothing has been stored, or if the stored credentials are invalid,
    the OAuth2 flow is completed to obtain the new credentials.

    Returns:
        Credentials, the obtained credential.
    """
    home_dir = os.path.expanduser('~')
    credential_dir = os.path.join(home_dir, '.credentials')
    if not os.path.exists(credential_dir):
        os.makedirs(credential_dir)
    credential_path = os.path.join(credential_dir,
                                   'sendEmail.json')

    store = oauth2client.file.Storage(credential_path)
    credentials = store.get()
    if not credentials or credentials.invalid:
        flow = client.flow_from_clientsecrets(CLIENT_SECRET_FILE, SCOPES)
        flow.user_agent = APPLICATION_NAME
        if flags:
            credentials = tools.run_flow(flow, store, flags)
        else: # Needed only for compatibility with Python 2.6
            credentials = tools.run(flow, store)
        print('Storing credentials to ' + credential_path)
    return credentials

if __name__ == "__main__":

    try:
        credentials = get_credentials()
        http = credentials.authorize(httplib2.Http())
        service = discovery.build('gmail', 'v1', http=http)
        SendMessage(service, "me", CreateMessage("[email protected]", "[email protected]", "Test gmail automation", "Hello world"))

    except Exception, e:
        print e
        raise

Note that if you encounter the error Insufficient Permission, one possible reason is that the scope in program is not set correctly.
The other possible reason may be that you need to delete the storage json file (“sendEmail.json” in this program) and refresh your program. More details may be seen in this post.

Answered By: ccy

I’m including some code that has been updated for python 3 usage – it seems to send emails once you get the necessary permissions and OAuth tokens working. It’s mostly based off the Google API website samples.

from __future__ import print_function

import base64
import os
from email.mime.text import MIMEText

import httplib2
from apiclient import discovery
from googleapiclient import errors
from oauth2client import client
from oauth2client import tools
from oauth2client.file import Storage

try:
    import argparse

    flags = argparse.ArgumentParser(parents=[tools.argparser]).parse_args()
except ImportError:
    flags = None

# If modifying these scopes, delete your previously saved credentials
# at ~/.credentials/gmail-python-quickstart.json
SCOPES = 'https://www.googleapis.com/auth/gmail.send'
CLIENT_SECRET_FILE = 'client_secret.json'
APPLICATION_NAME = 'Gmail API Python Quickstart'


def get_credentials():
    """Gets valid user credentials from storage.

    If nothing has been stored, or if the stored credentials are invalid,
    the OAuth2 flow is completed to obtain the new credentials.

    Returns:
        Credentials, the obtained credential.
    """
    home_dir = os.path.expanduser('~')
    credential_dir = os.path.join(home_dir, '.credentials')
    if not os.path.exists(credential_dir):
        os.makedirs(credential_dir)
    credential_path = os.path.join(credential_dir,
                                   'gmail-python-quickstart.json')

    store = Storage(credential_path)
    credentials = store.get()
    if not credentials or credentials.invalid:
        flow = client.flow_from_clientsecrets(CLIENT_SECRET_FILE, SCOPES)
        flow.user_agent = APPLICATION_NAME
        if flags:
            credentials = tools.run_flow(flow, store, flags)
        else:  # Needed only for compatibility with Python 2.6
            credentials = tools.run(flow, store)
        print('Storing credentials to ' + credential_path)
    return credentials


to = '[email protected]'
sender = '[email protected]'
subject = 'test emails'
message_text = 'hello this is a text test message'
user_id = 'me'

def create_message(sender, to, subject, message_text):
    """Create a message for an email.

    Args:
      sender: Email address of the sender.
      to: Email address of the receiver.
      subject: The subject of the email message.
      message_text: The text of the email message.

    Returns:
      An object containing a base64url encoded email object.
    """
    message = MIMEText(message_text)
    message['to'] = to
    message['from'] = sender
    message['subject'] = subject
    return {'raw': (base64.urlsafe_b64encode(message.as_bytes()).decode())}


def send_message(service, user_id, message):
    """Send an email message.

    Args:
      service: Authorized Gmail API service instance.
      user_id: User's email address. The special value "me"
      can be used to indicate the authenticated user.
      message: Message to be sent.

    Returns:
      Sent Message.
    """
    try:
        message = (service.users().messages().send(userId=user_id, body=message)
                   .execute())
        print('Message Id: {}'.format(message['id']))
        return message
    except errors.HttpError as error:
        print('An error occurred: {}'.format(error))


def main():
    """Shows basic usage of the Gmail API.

    Creates a Gmail API service object and outputs a list of label names
    of the user's Gmail account.
    """
    credentials = get_credentials()
    http = credentials.authorize(httplib2.Http())
    service = discovery.build('gmail', 'v1', http=http)

    msg = create_message(sender,to,subject,message_text)
    message = (service.users().messages().send(userId=user_id, body=msg)
               .execute())
    print('Message Id: {}'.format(message['id']))
    results = service.users().messages().list(userId='me').execute()
    labels = results.get('labels', [])

    if not labels:
        print('No labels found.')
    else:
        print('Labels:')
        for label in labels:
            print(label['name'])


if __name__ == '__main__':
    main()
Answered By: jjisnow

Updated sample for Python 3, and GMail’s current API, below.

Note that to get the credentials.json file below, you’ll need to create an Oauth client ID credential here, after selecting the relevant GCP project. Once you’ve created it you’ll be shown the client key and client secret. Close that prompt, and click the down arrow next to the account. This is the file you’ll need.

enter image description here

import base64
import logging
import mimetypes
import os
import os.path
import pickle
from email.mime.text import MIMEText
from google_auth_oauthlib.flow import InstalledAppFlow
from google.auth.transport.requests import Request
from googleapiclient import errors
from googleapiclient.discovery import build

def get_service():
    """Gets an authorized Gmail API service instance.

    Returns:
        An authorized Gmail API service instance..
    """    

    # If modifying these scopes, delete the file token.pickle.
    SCOPES = [
        'https://www.googleapis.com/auth/gmail.readonly',
        'https://www.googleapis.com/auth/gmail.send',
    ]

    creds = None
    # The file token.pickle stores the user's access and refresh tokens, and is
    # created automatically when the authorization flow completes for the first
    # time.
    if os.path.exists('token.pickle'):
        with open('token.pickle', 'rb') as token:
            creds = pickle.load(token)
    # If there are no (valid) credentials available, let the user log in.
    if not creds or not creds.valid:
        if creds and creds.expired and creds.refresh_token:
            creds.refresh(Request())
        else:
            flow = InstalledAppFlow.from_client_secrets_file(
                'credentials.json', SCOPES)
            creds = flow.run_local_server(port=0)
        # Save the credentials for the next run
        with open('token.pickle', 'wb') as token:
            pickle.dump(creds, token)

    service = build('gmail', 'v1', credentials=creds)
    return service

def send_message(service, sender, message):
  """Send an email message.

  Args:
    service: Authorized Gmail API service instance.
    user_id: User's email address. The special value "me"
    can be used to indicate the authenticated user.
    message: Message to be sent.

  Returns:
    Sent Message.
  """
  try:
    sent_message = (service.users().messages().send(userId=sender, body=message)
               .execute())
    logging.info('Message Id: %s', sent_message['id'])
    return sent_message
  except errors.HttpError as error:
    logging.error('An HTTP error occurred: %s', error)

def create_message(sender, to, subject, message_text):
  """Create a message for an email.

  Args:
    sender: Email address of the sender.
    to: Email address of the receiver.
    subject: The subject of the email message.
    message_text: The text of the email message.

  Returns:
    An object containing a base64url encoded email object.
  """
  message = MIMEText(message_text)
  message['to'] = to
  message['from'] = sender
  message['subject'] = subject
  s = message.as_string()
  b = base64.urlsafe_b64encode(s.encode('utf-8'))
  return {'raw': b.decode('utf-8')}

if __name__ == '__main__':
    logging.basicConfig(
        format="[%(levelname)s] %(message)s",
        level=logging.INFO
    )

    try:
        service = get_service()
        message = create_message("[email protected]", "[email protected]", "Test subject", "Test body")
        send_message(service, "[email protected]", message)

    except Exception as e:
        logging.error(e)
        raise
Answered By: Steve Gore

it is very simple.
Go to Gmail account settings.
Search for "App passwords".
Generate an app password.
Use that password instead of the Gmail password.
The advantage of app password is that you don’t need to turn off two factor authentication and also you don’t need to allow insecure apps.

This is the official link about Google app passwords https://support.google.com/mail/answer/185833?hl=en-GB

Hope this helps

Answered By: Naga Sudhir
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