How can I skip the header in Python?

Question

This is my code. I am trying to

import the data from net
Skip 12 lines

Store the rest of the data in a variable and perform some simple operations.

 import urllib2 

 airtemp = urllib2.urlopen('http://coastwatch.glerl.noaa.gov/ftp/glsea/avgtemps/2013/glsea-temps2013_1024.dat').read(30000)
 airtemp = airtemp.split("n")

 lineskip1 = 0
 for line in airtemp:
     if lineskip1 <12:
         continue
     print line
     lineskip1+=1

But I’m not able to print the lines.

Asked By: maximusyoda

||

Source

Answer 1

You are continuing the loop without incrementing lineskip1, so the condition is always true.

lineskip1 = 0
for line in airtemp:
    lineskip1 += 1
    if lineskip1 <= 12:  # Skip lines numbered 1 through 12
        continue
    print line

A better method is to use enumerate to count the lines for you.

for i, line in enumerate(airtemp):
    if i < 12:  # Skip lines numbered 0 through 11
        continue
    print line

or to use itertools.islice:

from itertools import islice
for line in islice(airtemp, 12, None):  # Skip lines numbered 0 through 11
    print line

Answered By: chepner

Answer 2

I think a simple list slice will work:

for line in airtemp[12:]: # start at line 13
   print line

Answered By: Padraic Cunningham

How can I skip the header in Python?

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