Using Pandas to pd.read_excel() for multiple worksheets of the same workbook

You can also use the index for the sheet:

xls = pd.ExcelFile('path_to_file.xls')
sheet1 = xls.parse(0)

will give the first worksheet. for the second worksheet:

sheet2 = xls.parse(1)

You could also specify the sheet name as a parameter:

data_file = pd.read_excel('path_to_file.xls', sheet_name="sheet_name")

will upload only the sheet "sheet_name".

There are a few options:

Read all sheets directly into an ordered dictionary.

import pandas as pd

# for pandas version >= 0.21.0
sheet_to_df_map = pd.read_excel(file_name, sheet_name=None)

# for pandas version < 0.21.0
sheet_to_df_map = pd.read_excel(file_name, sheetname=None)

Read the first sheet directly into dataframe

df = pd.read_excel('excel_file_path.xls')
# this will read the first sheet into df

Read the excel file and get a list of sheets. Then chose and load the sheets.

xls = pd.ExcelFile('excel_file_path.xls')

# Now you can list all sheets in the file
xls.sheet_names
# ['house', 'house_extra', ...]

# to read just one sheet to dataframe:
df = pd.read_excel(file_name, sheet_name="house")

Read all sheets and store it in a dictionary. Same as first but more explicit.

# to read all sheets to a map
sheet_to_df_map = {}
for sheet_name in xls.sheet_names:
    sheet_to_df_map[sheet_name] = xls.parse(sheet_name)
    # you can also use sheet_index [0,1,2..] instead of sheet name.

Thanks @ihightower for pointing it out way to read all sheets and @toto_tico,@red-headphone for pointing out the version issue.

sheetname : string, int, mixed list of strings/ints, or None, default 0
Deprecated since version 0.21.0: Use sheet_name instead Source Link

Yes unfortunately it will always load the full file. If you’re doing this repeatedly probably best to extract the sheets to separate CSVs and then load separately. You can automate that process with d6tstack which also adds additional features like checking if all the columns are equal across all sheets or multiple Excel files.

import d6tstack
c = d6tstack.convert_xls.XLStoCSVMultiSheet('multisheet.xlsx')
c.convert_all() # ['multisheet-Sheet1.csv','multisheet-Sheet2.csv']

See d6tstack Excel examples

pd.read_excel('filename.xlsx') 

by default read the first sheet of workbook.

pd.read_excel('filename.xlsx', sheet_name = 'sheetname') 

read the specific sheet of workbook and

pd.read_excel('filename.xlsx', sheet_name = None) 

read all the worksheets from excel to pandas dataframe as a type of OrderedDict means nested dataframes, all the worksheets as dataframes collected inside dataframe and it’s type is OrderedDict.

If you have saved the excel file in the same folder as your python program (relative paths) then you just need to mention sheet number along with file name.

Example:

 data = pd.read_excel("wt_vs_ht.xlsx", "Sheet2")
 print(data)
 x = data.Height
 y = data.Weight
 plt.plot(x,y,'x')
 plt.show()

If you are interested in reading all sheets and merging them together. The best and fastest way to do it

sheet_to_df_map = pd.read_excel('path_to_file.xls', sheet_name=None)
mdf = pd.concat(sheet_to_df_map, axis=0, ignore_index=True)

This will convert all the sheet into a single data frame m_df

If:

• you want multiple, but not all, worksheets, and
• you want a single df as an output

Then, you can pass a list of worksheet names. Which you could populate manually:

import pandas as pd
    
path = "C:\Path\To\Your\Data\"
file = "data.xlsx"
sheet_lst_wanted = ["01_SomeName","05_SomeName","12_SomeName"] # tab names from Excel

### import and compile data ###
    
# read all sheets from list into an ordered dictionary    
dict_temp = pd.read_excel(path+file, sheet_name= sheet_lst_wanted)

# concatenate the ordered dict items into a dataframe
df = pd.concat(dict_temp, axis=0, ignore_index=True)

OR

A bit of automation is possible if your desired worksheets have a common naming convention that also allows you to differentiate from unwanted sheets:

# substitute following block for the sheet_lst_wanted line in above block

import xlrd

# string common to only worksheets you want
str_like = "SomeName" 
    
### create list of sheet names in Excel file ###
xls = xlrd.open_workbook(path+file, on_demand=True)
sheet_lst = xls.sheet_names()
    
### create list of sheets meeting criteria  ###
sheet_lst_wanted = []
    
for s in sheet_lst:
    # note: following conditional statement based on my sheets ending with the string defined in sheet_like
    if s[-len(str_like):] == str_like:
        sheet_lst_wanted.append(s)
    else:
        pass

There are various options depending on the use case:

1. If one doesn’t know the sheets names.

2. If the sheets name is not relevant.

3. If one knows the name of the sheets.

Below we will look closely at each of the options.

See the Notes section for information such as finding out the sheet names.

---

Option 1

If one doesn’t know the sheets names

# Read all sheets in your File
df = pd.read_excel('FILENAME.xlsx', sheet_name=None)
    
# Prints all the sheets name in an ordered dictionary
print(df.keys())

Then, depending on the sheet one wants to read, one can pass each of them to a specific dataframe, such as

sheet1_df = pd.read_excel('FILENAME.xlsx', sheet_name=SHEET1NAME)
sheet2_df = pd.read_excel('FILENAME.xlsx', sheet_name=SHEET2NAME)

---

Option 2

If the name is not relevant and all one cares about is the position of the sheet. Let’s say one wants only the first sheet

# Read all sheets in your File
df = pd.read_excel('FILENAME.xlsx', sheet_name=None)

sheet1 = list(df.keys())[0]

Then, depending on the sheet name, one can pass each it to a specific dataframe, such as

sheet1_df = pd.read_excel('FILENAME.xlsx', sheet_name=SHEET1NAME)

---

Option 3

Here we will consider the case where one knows the name of the sheets.
For the examples, one will consider that there are three sheets named Sheet1, Sheet2, and Sheet3. The content in each is the same, and looks like this

     0         1     2
0   85   January  2000
1   95  February  2001
2  105     March  2002
3  115     April  2003
4  125       May  2004
5  135      June  2005

With this, depending on one’s goals, there are multiple approaches:

• Store everything in same dataframe. One approach would be to concat the sheets as follows

  sheets = ['Sheet1', 'Sheet2', 'Sheet3']
  df = pd.concat([pd.read_excel('FILENAME.xlsx', sheet_name = sheet) for sheet in sheets], ignore_index = True)
  
  [Out]:
  
        0         1     2
  0    85   January  2000
  1    95  February  2001
  2   105     March  2002
  3   115     April  2003
  4   125       May  2004
  5   135      June  2005
  6    85   January  2000
  7    95  February  2001
  8   105     March  2002
  9   115     April  2003
  10  125       May  2004
  11  135      June  2005
  12   85   January  2000
  13   95  February  2001
  14  105     March  2002
  15  115     April  2003
  16  125       May  2004
  17  135      June  2005
  

  Basically, this how pandas.concat works (Source):

  

• Store each sheet in a different dataframe (let’s say, df1, df2, …)

  sheets = ['Sheet1', 'Sheet2', 'Sheet3']
  
  for i, sheet in enumerate(sheets):
      globals()['df' + str(i + 1)] = pd.read_excel('FILENAME.xlsx', sheet_name = sheet)
  
  [Out]:
  
  # df1
       0         1     2
  0   85   January  2000
  1   95  February  2001
  2  105     March  2002
  3  115     April  2003
  4  125       May  2004
  5  135      June  2005
  
  # df2
       0         1     2
  0   85   January  2000
  1   95  February  2001
  2  105     March  2002
  3  115     April  2003
  4  125       May  2004
  5  135      June  2005
  
  # df3
       0         1     2
  0   85   January  2000
  1   95  February  2001
  2  105     March  2002
  3  115     April  2003
  4  125       May  2004
  5  135      June  2005
  

---

Notes:

• If one wants to know the sheets names, one can use the ExcelFile class as follows

  sheets = pd.ExcelFile('FILENAME.xlsx').sheet_names
  
  [Out]: ['Sheet1', 'Sheet2', 'Sheet3']
  

• In this case one is assuming that the file FILENAME.xlsx is on the same directory as the script one is running.

  • If the file is in a folder of the current directory called Data, one way would be to use r'./Data/FILENAME.xlsx' create a variable, such as path as follows

     path = r'./Data/Test.xlsx'
    
     df = pd.read_excel(r'./Data/FILENAME.xlsx', sheet_name=None)
    

• This might be a relevant read.

df = pd.read_excel('FileName.xlsx', 'SheetName')

This will read sheet SheetName from file FileName.xlsx

You can read all the sheets using the following lines

import pandas as pd
file_instance = pd.ExcelFile('your_file.xlsx')

main_df = pd.concat([pd.read_excel('your_file.xlsx', sheet_name=name) for name in file_instance.sheet_names] , axis=0)