Flipping zeroes and ones in one-dimensional NumPy array

Question:

I have a one-dimensional NumPy array that consists of zeroes and ones like so:

array([0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1])

I’d like a quick way to just “flip” the values such that zeroes become ones, and ones become zeroes, resulting in a NumPy array like this:

array([1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0])

Is there an easy one-liner for this? I looked at the fliplr() function, but this seems to require NumPy arrays of dimensions two or greater. I’m sure there’s a fairly simple answer, but any help would be appreciated.

Asked By: kylerthecreator

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Answers:

There must be something in your Q that i do not understand…

Anyway

In [2]: from numpy import array

In [3]: a = array((1,0,0,1,1,0,0))

In [4]: b = 1-a

In [5]: print a ; print b
[1 0 0 1 1 0 0]
[0 1 1 0 0 1 1]

In [6]: 
Answered By: gboffi
answer = numpy.ones_like(a) - a
Answered By: heltonbiker

another superfluous option:

numpy.logical_not(a).astype(int)
Answered By: John Greenall

A sign that you should probably be using a boolean datatype

a = np.array([0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1], dtype=np.bool)
# or
b = ~a
b = np.logical_not(a)
Answered By: YXD

I also found a way to do it:

In [1]: from numpy import array

In [2]: a = array([1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0])

In [3]: b = (~a.astype(bool)).astype(int)


In [4]: print(a); print(b)
[1 1 1 1 1 0 0 0 0 0 0 0 0 0 0]
[0 0 0 0 0 1 1 1 1 1 1 1 1 1 1]

Still, I think that @gboffi’s answer is the best. I’d have upvoted it but I don’t have enough reputation yet 🙁

Answered By: Mikolaj Buchwald
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