How to check if all elements in a list are whole numbers

Question

If I have a list such as :

List = [12,6,3,5,1.2,5.5]

Is there a way I can check if all the numbers are whole numbers? I tried something like

def isWhole(d): 
if (d%1 == 0 ) : for z in List return true.

That is obviously terribly wrong. What can I do?

Asked By: bob9123

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Source

Answer 1

So you want integers and floats that are equal to integers?

def is_whole(d):
    """Whether or not d is a whole number."""
    return isinstance(d, int) or (isinstance(d, float) and d.is_integer())

In use:

>>> for test in (1, 1.0, 1.1, "1"):
    print(repr(test), is_whole(test))


1 True # integer 
1.0 True # float equal to integer
1.1 False # float not equal to integer
'1' False # neither integer nor float

You can then apply this to your list with all and map:

if all(map(is_whole, List)):

or a generator expression:

if all(is_whole(d) for d in List):

Answered By: jonrsharpe

Answer 2

Simple solution for a list L:

def isWhole(L):
    for i in L:
        if i%1 != 0:
            return False
    return True

Answered By: Ogaday

Answer 3

List = [12,6,3,5,1.2,5.5]

for i in List:

if i%1 != 0 :
    print(False)
    break

Answered By: gaurav_syscom

Answer 4

if your list is lst = [12,6,3,5,1.2,5.5]
you can do this.

lst = [12,6,3,5,1.2,5.5]
print(all(isinstance(i,int) for i in lst))

it prints "True" if your list contains whole numbers, if not "False"

Answered By: Sivakumar Revuri

How to check if all elements in a list are whole numbers

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