how to get text from within a tag, but ignore other child tags
Question:
I am working with beautiful soup.
I have a html string:
<div><b>ignore this</b>get this</div>
How do I retrieve “get this”, while ignoring “ignore this“
Thanks
Answers:
You can get the div
text just not recursively retrieving the children texts:
>>> from bs4 import BeautifulSoup
>>> soup = BeautifulSoup('<div><b>ignore this</b>get this</div>')
>>> soup.div.find(text=True, recursive=False)
u'get this'
This works independently of the position of the text with respect of the children:
>>> soup = BeautifulSoup('<div>get this<b>ignore this</b></div>')
>>> soup.div.find(text=True, recursive=False)
u'get this'
def getonlytext(s):
beg_tag = s.find('<')
while not beg_tag == -1:
fin_tag = s.find('>')
s = s.replace(s[beg_tag:fin_tag+1], '')
beg_tag = s.find('<')
return s
I am working with beautiful soup.
I have a html string:
<div><b>ignore this</b>get this</div>
How do I retrieve “get this”, while ignoring “ignore this“
Thanks
You can get the div
text just not recursively retrieving the children texts:
>>> from bs4 import BeautifulSoup
>>> soup = BeautifulSoup('<div><b>ignore this</b>get this</div>')
>>> soup.div.find(text=True, recursive=False)
u'get this'
This works independently of the position of the text with respect of the children:
>>> soup = BeautifulSoup('<div>get this<b>ignore this</b></div>')
>>> soup.div.find(text=True, recursive=False)
u'get this'
def getonlytext(s):
beg_tag = s.find('<')
while not beg_tag == -1:
fin_tag = s.find('>')
s = s.replace(s[beg_tag:fin_tag+1], '')
beg_tag = s.find('<')
return s