make a string including x in python

Question

I would like to make a string that includes “x” but I get

invalid x escape

error.

a = 'x'+''.join(lstDES[100][:2])+'x'+''.join(lstDES[100][2:])

How can I correct it?

Asked By: user1914367

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Source

Answer 1

Double the backslash to stop Python from interpreting it as a special character:

'\x'

or use a raw string literal:

r'x'

In regular Python string literals, backslashes signal the start of an escape sequence, and x is a sequence that defines characters by their hexadecimal byte value.

You could use string formatting instead of all the concatenation here:

r'x{0[0]}{0[1]}x{0[2]}{0[3]}'.format(lstDES[100])

If you are trying to define two bytes based on the hex values from lstDES[100] then you’ll have to use a different approach; producing a string with the characters , x and two hex digits will not magically invoke the same interpretation Python uses for string literals.

You would use the binascii.unhexlify() function for that instead:

import binascii

a = binascii.unhexlify(''.join(lstDES[100][:4]))

Answered By: Martijn Pieters

Answer 2

In Python is used to escape characters, such as n for a newline or t for a tab.

To have the literal string 'x' you need to use two backslashes, one to effectively escape the other, so it becomes '\x'.

In [199]: a = '\x'

In [200]: print(a)
x

Answered By: Ffisegydd

Answer 3

You need \x because used for escape the characters :

>>> s='\x'+'a'
>>> print s
xa

Answered By: Mazdak

Answer 4

Try to make a raw string as follows:

a = r'x'+''.join(lstDES[100][:2]) + r'x'+''.join(lstDES[100][2:])

Answered By: Necrolyte2

make a string including x in python

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