running code if try statements were successful in python

Question

I was wondering if in python there was a simple way to run code if a try statement was successful that wasn’t in the try statement itself. Is that what the else or finally commands do (I didn’t understand their documentation)? I know I could use code like this:

successful = False
try:
    #code that might fail
    successful = True
except:
    #error handling if code failed
if successful:
    #code to run if try was successful that isn't part of try

but I was wondering if there was a shorter way.

Asked By: None

||

Source

Answer 1

You are looking for the else keyword:

try:
    #code that might fail
except SomeException:
    #error handling if code failed
else:
    # do this if no exception occured

Answered By: unutbu

Answer 2

You want else:

for i in [0, 1]:
    try:
        print '10 / %i: ' % i, 10 / i
    except:
        print 'Uh-Oh'
    else:
        print 'Yay!'

Answered By: Jesse Aldridge

Answer 3

Your try block should be the code you want to execute, and your except should be killing the program. I’d need to understand your object better to give a better answer.

In OO programming, you want to “Tell, don’t ask” so keep all the logic that should happen in the try block, and then your error handling in the except block.

Answered By: Zee Spencer

running code if try statements were successful in python

Question:

Answers: