Why doesn't itertools.combination_with_replacement give 27 results for length-3 combinations of 3 values?

Question

Below is my code

import itertools
a = [1,2,3]
for i in itertools.combination_with_replacement(a,3):
    print i

Output

(1, 1, 1),(1, 1, 2)
(1, 1, 3),(1, 2, 2)
(1, 2, 3),(1, 3, 3)
(2, 2, 2),(2, 2, 3)
(2, 3, 3),(3, 3, 3)

Only 10 result is print out, but by formula, it should be 3^3 = 27 output.

So may i know, how to get the other output?
Sincerely thank for your time and suggestion.

Asked By: Math

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Answer 1

You want cartesian product, not combinations.

import itertools
print list(itertools.product([1, 2, 3], repeat=3))

Answered By: Paul Hankin

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