Super init vs. parent.init

Question

A Python subclass can be initialized with or without a call to super(), as shown below

class Parent(object):
    ...

class Child(Parent):

    def __init__(self):
        super(Child, self).__init__()


class Child(Parent):

    def __init__(self):
        Parent.__init__(self)

What is the difference between these cases, and is one generally preferable to the other?

Asked By: Adam Hughes

||

Source

Answer 1

The purpose of super is to handle inheritance diamonds. If the class
inheritance structure uses only single-inheritance, then using super() will
result in the same calls as explicit calls to the “parent” class.

Consider this inheritance diamond:

class A(object):
    def __init__(self):
        print('Running A.__init__')
        super(A,self).__init__()

class B(A):
    def __init__(self):
        print('Running B.__init__')        
        super(B,self).__init__()

class C(A):
    def __init__(self):
        print('Running C.__init__')
        super(C,self).__init__()

class D(B,C):
    def __init__(self):
        print('Running D.__init__')
        super(D,self).__init__()

foo = D()

which prints

Running D.__init__
Running B.__init__
Running C.__init__
Running A.__init__

while if we change B to B2 and use explicit calls to the parent __init__:

class B2(A):
    def __init__(self):
        print('Running B.__init__')        
        A.__init__(self) 

class D2(B2,C):
    def __init__(self):
        print('Running D.__init__')
        super(D2,self).__init__()

bar = D2()

then the chain of init calls becomes

Running D.__init__
Running B.__init__
Running A.__init__

So the call to C.__init__ is skipped entirely.

There is no one preferred option.

If you can guarantee that you do not want to support multiple inheritance then
explicit parent calls are simpler and clearer.

If you wish to support multiple inheritance now or in the future, then you need to use super(). But understand that there are some pitfalls involved with using super, but with proper use these pitfalls can be avoided.

Answered By: unutbu

Answer 2

The primary purpose of super(Child, self).__init__() is allow initialization run properly in the case of multiple inheritance with diamond inheritance structures. If you explicitly call the base class constructors with multiple inheritance some initializers may be called twice. With single inheritance, there is no functional difference between using super and explicitly invoking the base class __init__() method. Note that because all python new-style classes subclass object, multiple inheritance always involves diamond inheritance.

super has a lesser benefit of reducing requires changes if you rename or change the base class.

In python 3, the arguments to super are optional, so you can just do super().__init__(). Python 2 still requires you to provide the arguments explicitly.

Answered By: Evan

Super init vs. parent.init

Question:

Answers:

Super init vs. parent.__init__

Question:

Answers:

Super init vs. parent.init