Print a dictionary into a table

Question

I have a dictionary:

dic={'Tim':3, 'Kate':2}

I would like to output it as:

Name Age
Tim 3
Kate 2

Is it a good way to first convert them into a list of dictionaries,

lst = [{'Name':'Tim', 'Age':3}, {'Name':'Kate', 'Age':2}]

and then write them into a table, by the method in https://stackoverflow.com/a/10373268/156458?

Or is there a way better in some sense?

Asked By: Tim

||

Source

Answer 1

You can do it directly as in

>>> print("NametAge")
Name  Age
>>> for i in dic:
...     print("{}t{}".format(i,dic[i]))
... 
Tim 3
Kate    2
>>>

It displays even better if executed as a script

Name    Age
Tim     3
Kate    2

And for the other representation

lst = [{'Name':'Tim', 'Age':3}, {'Name':'Kate', 'Age':2}]
print("NametAge")
for i in lst:
    print("{}t{}".format(i['Name'],i['Age']))

And for your final question – Is it a good way to first convert them into a list of dictionaries Answer is No, A dictionary is hashed and provides faster access than lists

Answered By: Bhargav Rao

Answer 2

Rather than convert to a list of dictionaries, directly use the .items of the dict to get the values to display on each line:

print('Name Age')
for name, age in dic.items():
    print(f'{name} {age}')

In versions before 3.6 (lacking f-string support), we can do:

print('Name Age')
for name, age in dic.items():
    print('{} {}'.format(name, age))

Answered By: Francis Colas

Answer 3

You could use pandas.

In [15]: import pandas as pd

In [16]: df = pd.DataFrame({'Tim':3, 'Kate':2}.items(), columns=["name", "age"]) 

In [17]: df
Out[17]: 
   name  age
0   Tim    3
1  Kate    2

Answered By: Akavall

Answer 4

Iterate dictionary and print every item.

Demo:

>>> dic = {'Tim':3, 'Kate':2}
>>> print "NametAge"
Name    Age
>>> for i in dic.items():
...    print "%st%s"%(i[0], i[1])
... 
Tim 3
Kate    2
>>>

By CSV module

>>> import csv
>>> dic = {'Tim':3, 'Kate':2}
>>> with open("output.csv", 'wb') as fp:
...     root = csv.writer(fp, delimiter='t')
...     root.writerow(["Name", "Age"])
...     for i,j in dic.items():
...         root.writerow([i, j])
... 
>>>

Output: output.csv file content

Name    Age
Tim     3
Kate    2

We can use root.writerows(dic.items()) also

Answered By: Vivek Sable

Answer 5

You can do it this way,

format = "{:<10}{:<10}"    
    print format.format("Name","Age")
    for name,age in dic.iteritems():
       print format.format(name,age)

I have written a simple library to pretty print dictionary as a table
https://github.com/varadchoudhari/Neat-Dictionary
which uses a similar implementation

Answered By: vardos

Answer 6

If you go for higher numbers, then having number in the first column is usually a safer bet as you never know how long a name can be.

Given python3:

dic={'Foo':1234, 'Bar':5, 'Baz':123467}

This:

print("Count".rjust(9), "Name")
rint("n".join(f'{v:9,} {k}' for k,v in dic.items()))

Prints

    Count Name
    1,234 Foo
        5 Bar
  123,467 Baz

Answered By: hansaplast

Answer 7

To improve upon Francis Colas’s answer, you can make it simpler by using f strings:

print('Name Age')
for name, age in dic.items():
  print(f'{name} {age}')

Answered By: user16386910

Answer 8

for each in zip(*([i] + (j) for i, j in c.items())):
    print(*each)

Answered By: Yash Goyal

Print a dictionary into a table

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