hexToBinary dictionary

Question

So I am working on this problem: Recall from the Number Systems unit the method for converting hexadecimal numbers to
binary by converting each hex digit to its equivalent four binary digits. Write a Python
function named hexToBinary with parameters (number, table) that uses this algorithm to
convert a hexadecimal number to a (return) binary number. The algorithm visits each digit
in the hexadecimal number, selecting from table the corresponding four bits that represent
that digit in binary and then adds these bits to the result string.

This is the code I have written, but I’m not getting it able to work properly:

def hexToBinary (hex, table):
    hexToBinary= {'0':'0000', '1':'0001', '2':'0010','3':'0011', '4': '0100', '5': '0101', '6':'0110', '7': '0111', '8': '1000', '9': '1001', 'A': '1010', 'B': '1011', 'C': '1100', 'D': '1101', 'E': '1110', 'F': '1111'}
    final_hexToBinary = ''
    for hex in hexToBinary:
        final_hexToBinary+=hex
        print(final_hexToBinary)

I am wondering what is wrong with the function, I have a feeling it is a simple mistake.

Asked By: MSK

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Source

Answer 1

You forget this:

final_hexToBinary += hexToBinary[hex]

Also:

‘table’ — not used var.
hexToBinary name of function and dict.
hex — reserved word, argument and iterator.

It’s not a problem, but sometime you can achieve mistake with that.

Answered By: Denis Lazarev

Answer 2

def hexToBinary (hex, table):

    final_hexToBinary = ''
    for each  in hex:
        final_hexToBinary+=table[each]
    print(final_hexToBinary)
hexToBinaryTable = {'0':'0000', '1':'0001', '2':'0010','3':'0011', '4': '0100', '5': '0101', '6':'0110', '7': '0111', '8': '1000', '9': '1001', 'A': '1010', 'B': '1011', 'C': '1100', 'D': '1101', 'E': '1110', 'F': '1111'}
hexToBinary("3FB",hexToBinaryTable)

As mentioned it comment your might want to look up the dictionary.
If you need not implement the function go for the one mentioned by john galt in comment.

Answered By: WannaBeCoder

Answer 3

if I am correct you are trying this:

def hexToBinary(my_hex):
    hexToBinary= {'0':'0000', '1':'0001', '2':'0010','3':'0011', '4': '0100', '5': '0101', '6':'0110', '7': '0111', '8': '1000', '9': '1001', 'A': '1010', 'B': '1011', 'C': '1100', 'D': '1101', 'E': '1110', 'F': '1111'}
    final_hexToBinary = ''
    for x in my_hex:    # here it should be my_hex instead of table
        final_hexToBinary += hexToBinary[x]  # here was the mistake
    print(final_hexToBinary)

hexToBinary("ABC12")

output:

10101011110000010010

NOTE: dont use `hex` as variable name its built-in python

Answered By: Hackaholic

Answer 4

Try this:

hexToBinary= {'0':'0000', '1':'0001', '2':'0010','3':'0011', '4': '0100', '5': '0101', '6':'0110', '7': '0111', '8': '1000', '9': '1001', 'A': '1010', 'B': '1011', 'C': '1100', 'D': '1101', 'E': '1110', 'F': '1111'}
to_conv= input("enter a num: ")
final_hexToBinary = ''
for hex in to_conv:
    final_hexToBinary += hexToBinary.get(hex,"!!") + " "
print(final_hexToBinary)

Answered By: utahnotu

hexToBinary dictionary

Question:

Answers:

NOTE: dont use `hex` as variable name its built-in python

hexToBinary dictionary

Question:

Answers:

NOTE: dont use hex as variable name its built-in python

NOTE: dont use `hex` as variable name its built-in python