How do I change directory back to my original working directory with Python?

Question:

I have a function that resembles the one below. I’m not sure how to use the os module to get back to my original working directory at the conclusion of the jar’s execution.

def run(): 
    owd = os.getcwd()
    #first change dir to build_dir path
    os.chdir(testDir)
    #run jar from test directory
    os.system(cmd)
    #change dir back to original working directory (owd)

note: I think my code formatting is off – not sure why. My apologies in advance

Asked By: Amara

||

Answers:

You simply need to add the line:

os.chdir(owd)

Just a note this was also answered in your other question.

Answered By: grieve

os.chdir(owd) should do the trick (like you’ve done when changing to testDir)

Answered By: Nethanel

The advice to use os.chdir(owd) is good. It would be wise to put the code which needs the changed directory in a try:finally block (or in python 2.6 and later, a with: block.) That reduces the risk that you will accidentally put a return in the code before the change back to the original directory.

def run(): 
    owd = os.getcwd()
    try:
        #first change dir to build_dir path
        os.chdir(testDir)
        #run jar from test directory
        os.system(cmd)
    finally:
        #change dir back to original working directory (owd)
        os.chdir(owd)
Answered By: Alex Coventry

Python is case sensitive so when typing the path make sure it’s the same as the directory
you want to set.

import os

os.getcwd()

os.chdir('C:\')
Answered By: eagle3ye

A context manager is a very appropriate tool for this job:

from contextlib import contextmanager

@contextmanager
def cwd(path):
    oldpwd = os.getcwd()
    os.chdir(path)
    try:
        yield
    finally:
        os.chdir(oldpwd)

…used as:

os.chdir('/tmp') # for testing purposes, be in a known directory
print(f'before context manager: {os.getcwd()}')
with cwd('/'):
    # code inside this block, and only inside this block, is in the new directory
    print(f'inside context manager: {os.getcwd()}')
print(f'after context manager: {os.getcwd()}')

…which will yield something like:

before context manager: /tmp
inside context manager: /
after context manager: /tmp

This is actually superior to the cd - shell builtin, inasmuch as it also takes care of changing directories back when a block is exited due to an exception being thrown.


For your specific use case, this would instead be:

with cwd(testDir):
    os.system(cmd)

Another option to consider is using subprocess.call() instead of os.system(), which will let you specify a working directory for the command to run:

# note: better to modify this to not need shell=True if possible
subprocess.call(cmd, cwd=testDir, shell=True)

… which would prevent you from needing to change the interpreter’s directory at all.

Note that now it is recommended to use subprocess.run (instead of call) but the same arguments are available, and in particular cwd: https://docs.python.org/3/library/subprocess.html#using-the-subprocess-module.

Answered By: Charles Duffy

A context-manager is overkill for this situation (executing a system command). The best solution is to use the subprocess module instead (Python 2.4 onwards) and the run or popen methods with the cwd argument.

So, your code can be replaced with:

def run(): 
    #run jar from test directory
    subprocess.run(cmd, cwd=testDir)

See https://bugs.python.org/issue25625 and https://docs.python.org/3/library/subprocess.html#subprocess-replacements.

Answered By: Nzbuu

I looked around the answers on StackOverflow and eventually decided to write my own decorator for this purpose:

from collections.abc import Callable
from functools import wraps
from typing import ParamSpec, TypeVar


T = TypeVar('T')
P = ParamSpec('P')
    
    
def enter_subdir(subdir: str) -> Callable[[Callable[P, T]], Callable[P, T]]:
    """During the execution of a function, temporarily enter a subdirectory."""

    def decorator(function: Callable[P, T]) -> Callable[P, T]:
        @wraps(function)
        def wrapper(*args, **kwargs) -> T:
            os.makedirs(subdir, exist_ok=True)
            os.chdir(subdir)
            result = function(*args, **kwargs)
            os.chdir("..")
            return result

        return wrapper

    return decorator
Answered By: Vladimir Vilimaitis

Python 3.11 update:

You can now simply use contextlib.chdir from stdlib. It changes the directory when entering the block, it then restores the old directory back:

from contextlib import chdir
from os import getcwd

print(f"Before: {getcwd()}")
with chdir("/"):
    print(f"inside: {getcwd()}")
print(f"after: {getcwd()}")
Answered By: S.B
Categories: questions Tags:
Answers are sorted by their score. The answer accepted by the question owner as the best is marked with
at the top-right corner.