Different result with roc_auc_score() and auc()

Question

I have trouble understanding the difference (if there is one) between roc_auc_score() and auc() in scikit-learn.

Im tying to predict a binary output with imbalanced classes (around 1.5% for Y=1).

Classifier

model_logit = LogisticRegression(class_weight='auto')
model_logit.fit(X_train_ridge, Y_train)

Roc curve

false_positive_rate, true_positive_rate, thresholds = roc_curve(Y_test, clf.predict_proba(xtest)[:,1])

AUC’s

auc(false_positive_rate, true_positive_rate)
Out[490]: 0.82338034042531527

and

roc_auc_score(Y_test, clf.predict(xtest))
Out[493]: 0.75944737191205602

Somebody can explain this difference ? I thought both were just calculating the area under the ROC curve. Might be because of the imbalanced dataset but I could not figure out why.

Thanks!

Asked By: gowithefloww

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Source

Answer 1

AUC is not always area under the curve of a ROC curve. Area Under the Curve is an (abstract) area under some curve, so it is a more general thing than AUROC. With imbalanced classes, it may be better to find AUC for a precision-recall curve.

See sklearn source for roc_auc_score:

def roc_auc_score(y_true, y_score, average="macro", sample_weight=None):
    # <...> docstring <...>
    def _binary_roc_auc_score(y_true, y_score, sample_weight=None):
            # <...> bla-bla <...>

            fpr, tpr, tresholds = roc_curve(y_true, y_score,
                                            sample_weight=sample_weight)
            return auc(fpr, tpr, reorder=True)

    return _average_binary_score(
        _binary_roc_auc_score, y_true, y_score, average,
        sample_weight=sample_weight)

As you can see, this first gets a roc curve, and then calls auc() to get the area.

I guess your problem is the predict_proba() call. For a normal predict() the outputs are always the same:

import numpy as np
from sklearn.linear_model import LogisticRegression
from sklearn.metrics import roc_curve, auc, roc_auc_score

est = LogisticRegression(class_weight='auto')
X = np.random.rand(10, 2)
y = np.random.randint(2, size=10)
est.fit(X, y)

false_positive_rate, true_positive_rate, thresholds = roc_curve(y, est.predict(X))
print auc(false_positive_rate, true_positive_rate)
# 0.857142857143
print roc_auc_score(y, est.predict(X))
# 0.857142857143

If you change the above for this, you’ll sometimes get different outputs:

false_positive_rate, true_positive_rate, thresholds = roc_curve(y, est.predict_proba(X)[:,1])
# may differ
print auc(false_positive_rate, true_positive_rate)
print roc_auc_score(y, est.predict(X))

Answered By: oopcode

Answer 2

predict returns only one class or the other. Then you compute a ROC with the results of predict on a classifier, there are only three thresholds (trial all one class, trivial all the other class, and in between). Your ROC curve looks like this:

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Meanwhile, predict_proba() returns an entire range of probabilities, so now you can put more than three thresholds on your data.

             .......................
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          ...|
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     .....|
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Hence different areas.

Answered By: Andreus

Answer 3

When you use the y_pred (class labels), you already decided on
the threshold. When you use y_prob (positive class probability)
you are open to the threshold, and the ROC Curve should help
you decide the threshold.

For the first case you are using the probabilities:

y_probs = clf.predict_proba(xtest)[:,1]
fp_rate, tp_rate, thresholds = roc_curve(y_true, y_probs)
auc(fp_rate, tp_rate)

When you do that, you’re considering the AUC ‘before’ taking
a decision on the threshold you’ll be using.

In the second case, you are using the prediction (not the probabilities),
in that case, use ‘predict’ instead of ‘predict_proba’ for both and you
should get the same result.

y_pred = clf.predict(xtest)
fp_rate, tp_rate, thresholds = roc_curve(y_true, y_pred)
print auc(fp_rate, tp_rate)
# 0.857142857143

print roc_auc_score(y, y_pred)
# 0.857142857143

Answered By: Dayvid Oliveira

Different result with roc_auc_score() and auc()

Question:

Classifier

Roc curve

AUC’s

Answers: