How to represent matrices in python

Question:

How can I represent matrices in python?

Asked By: Bunny Rabbit

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Answers:

Python doesn’t have matrices. You can use a list of lists or NumPy

Answered By: Ed.
((1,2,3,4),
 (5,6,7,8),
 (9,0,1,2))

Using tuples instead of lists makes it marginally harder to change the data structure in unwanted ways.

If you are going to do extensive use of those, you are best off wrapping a true number array in a class, so you can define methods and properties on them. (Or, you could NumPy, SciPy, … if you are going to do your processing with those libraries.)

Answered By: badp

Take a look at this answer:

from numpy import matrix
from numpy import linalg
A = matrix( [[1,2,3],[11,12,13],[21,22,23]]) # Creates a matrix.
x = matrix( [[1],[2],[3]] )                  # Creates a matrix (like a column vector).
y = matrix( [[1,2,3]] )                      # Creates a matrix (like a row vector).
print A.T                                    # Transpose of A.
print A*x                                    # Matrix multiplication of A and x.
print A.I                                    # Inverse of A.
print linalg.solve(A, x)     # Solve the linear equation system.
Answered By: György Andrasek

If you are not going to use the NumPy library, you can use the nested list. This is code to implement the dynamic nested list (2-dimensional lists).

Let r is the number of rows

let r=3

m=[]
for i in range(r):
    m.append([int(x) for x in raw_input().split()])

Any time you can append a row using

m.append([int(x) for x in raw_input().split()])

Above, you have to enter the matrix row-wise. To insert a column:

for i in m:
    i.append(x) # x is the value to be added in column

To print the matrix:

print m       # all in single row

for i in m:
    print i   # each row in a different line
Answered By: Gautam Seth
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