Get loop count inside a for-loop
Question:
This for loop iterates over all elements in a list:
for item in my_list:
print item
Is there a way to know within the loop how many times I’ve been looping so far? For instance, I want to take a list and after I’ve processed ten elements I want to do something with them.
The alternatives I thought about would be something like:
count=0
for item in my_list:
print item
count +=1
if count % 10 == 0:
print 'did ten'
Or:
for count in range(0,len(my_list)):
print my_list[count]
if count % 10 == 0:
print 'did ten'
Is there a better way (just like the for item in my_list) to get the number of iterations so far?
Answers:
The pythonic way is to use enumerate:
for idx, item in enumerate(my_list):
Agree with Nick.
Here is more elaborated code.
#count=0
for idx, item in enumerate(list):
print item
#count +=1
#if count % 10 == 0:
if (idx+1) % 10 == 0:
print 'did ten'
I have commented out the count variable in your code.
I know rather old question but….came across looking other thing so I give my shot:
[each*2 for each in [1,2,3,4,5] if each % 10 == 0])
Using zip function we can get both element and index.
countries = ['Pakistan','India','China','Russia','USA']
for index, element in zip(range(0,countries),countries):
print('Index : ',index)
print(' Element : ', element,'n')
output : Index : 0 Element : Pakistan ...
See also :
This is something you can also do to check for the list index. When it hits the list index 9, which is the 10th element of the list, it will print "did ten".
for item in list:
print item
if list.index(item) == 9:
print 'did ten'
This for loop iterates over all elements in a list:
for item in my_list:
print item
Is there a way to know within the loop how many times I’ve been looping so far? For instance, I want to take a list and after I’ve processed ten elements I want to do something with them.
The alternatives I thought about would be something like:
count=0
for item in my_list:
print item
count +=1
if count % 10 == 0:
print 'did ten'
Or:
for count in range(0,len(my_list)):
print my_list[count]
if count % 10 == 0:
print 'did ten'
Is there a better way (just like the for item in my_list) to get the number of iterations so far?
The pythonic way is to use enumerate:
for idx, item in enumerate(my_list):
Agree with Nick.
Here is more elaborated code.
#count=0
for idx, item in enumerate(list):
print item
#count +=1
#if count % 10 == 0:
if (idx+1) % 10 == 0:
print 'did ten'
I have commented out the count variable in your code.
I know rather old question but….came across looking other thing so I give my shot:
[each*2 for each in [1,2,3,4,5] if each % 10 == 0])
Using zip function we can get both element and index.
countries = ['Pakistan','India','China','Russia','USA']
for index, element in zip(range(0,countries),countries):
print('Index : ',index)
print(' Element : ', element,'n')
output : Index : 0 Element : Pakistan ...
See also :
This is something you can also do to check for the list index. When it hits the list index 9, which is the 10th element of the list, it will print "did ten".
for item in list:
print item
if list.index(item) == 9:
print 'did ten'