Rotate tick labels for seaborn barplot

Question:

I am trying to display a chart with rotated x-axis labels, but the chart is not displaying.

import seaborn as sns
%matplotlib inline

yellow='#FFB11E'
by_school=sns.barplot(x ='Organization Name',y ='Score',data = combined.sort('Organization Name'),color=yellow,ci=None)

At this point I can see the image, but after I set the xticklabel, I don’t see the image anymore only an object reference. (I would post the image, but I don’t enough reputation :()

by_school.set_xticklabels('Organization Name',rotation=45)

<matplotlib.axes._subplots.AxesSubplot at 0x3971a6a0>

A similar question is posted here: Rotate label text in seaborn factorplot but the solution is not working.

Asked By: Laurennmc

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Answers:

You need a different method call, namely .set_rotation for each ticklables.
Since you already have the ticklabels, just change their rotations:

for item in by_school.get_xticklabels():
    item.set_rotation(45)

barplot returns a matplotlib.axes object (as of seaborn 0.6.0), therefore you have to rotate the labels this way. In other cases, when the method returns a FacetGrid object, refer to Rotate label text in seaborn factorplot

Answered By: CT Zhu

If you come here to rotate the labels for a seaborn.heatmap, the following should work (based on @Aman’s answer at Rotate label text in seaborn factorplot)

pandas_frame = pd.DataFrame(data, index=names, columns=names)
heatmap = seaborn.heatmap(pandas_frame)
loc, labels = plt.xticks()
heatmap.set_xticklabels(labels, rotation=45)
heatmap.set_yticklabels(labels[::-1], rotation=45) # reversed order for y
Answered By: serv-inc

Use the following code statement:

by_school.set_xticklabels(by_school.get_xticklabels(), 
                          rotation=90, 
                          horizontalalignment='right')
Answered By: Amit Vikram Singh

This worked for me:

g.fig.autofmt_xdate()
Answered By: Kairat Sharshenbaev

You can rotate seaborn xticks like so:

sns.barplot(x='Organization Name', y='Score', data=df)

plt.xticks(rotation=70)
plt.tight_layout()
Answered By: wordsforthewise
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