Giving a column multiple indexes/headers

Question:

I am working with pandas dataframes that are essentially time series like this:

             level
Date              
1976-01-01  409.67
1976-02-01  409.58
1976-03-01  409.66
…

What I want to have, is multiple indexes/headers for the level column, like so:

           Station1                   #Name of the datasource
           43.1977317,-4.6473648,5    #Lat/Lon of the source
           Precip                     #Type of data
Date              
1976-01-01  409.67
1976-02-01  409.58
1976-03-01  409.66
…

So essentially I am searching for something like

Mydata.columns.level1 = ['Station1']
Mydata.columns.level2 = ['Lat','Lon']
Mydata.columns.level3 = ['Precip']

Reason being that a single location can have multiple datasets, and that I want to be able to pick either all data from one location, or all data of a certain type from all locations, from a subsequent merged, big dataframe.

I can set up an example dataframe from the pandas documentation, and test my selection, but with my real data, I need a different way to set the indexes as in the example.

Example:

header = [np.array(['location','location','location','location2','location2','location2']), 
np.array(['S1','S2','S3','S1','S2','S3'])] 
df = pd.DataFrame(np.random.randn(5, 6), index=['a','b','c','d','e'], columns=header )   

Then I can pick data by data type:

df.loc(axis=1)[:,'S1']

   location  location2
         S1         S1
a -1.469932  -0.317262
b  0.047170   0.601172
c -0.257479  -0.242490
d  0.832949  -0.070383
e -0.628549  -2.319316

or location:

df['location']

         S1        S2        S3
a -1.469932 -1.544511 -1.373463
b  0.047170 -0.339423  1.351253
c -0.257479  1.140829  0.188291
d  0.832949  0.098170 -0.818513
e -0.628549 -0.158419  0.366167

Or am I just looking for the wrong terminology? Because 90% of all examples in the documentation, and the questions here only treat the vertical "stuff" (dates or abcde in my case) as index, and a quick df.index.values on my test data also just gets me the vertical array(['a', 'b', 'c', 'd', 'e'], dtype=object).

Asked By: JC_CL

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Answers:

You can use multiIndex to give multiple columns with names for each level. Use MultiIndex.from_product() to make multiIndex from cartesian products of multiple iterables.

header = pd.MultiIndex.from_product([['location1','location2'],
                                     ['S1','S2','S3']],
                                    names=['loc','S'])
df = pd.DataFrame(np.random.randn(5, 6), 
                  index=['a','b','c','d','e'], 
                  columns=header)

Two levels will be loc and S.

df
loc location1                     location2                    
S          S1        S2        S3        S1        S2        S3
a   -1.245988  0.858071 -1.433669  0.105300 -0.630531 -0.148113
b    1.132016  0.318813  0.949564 -0.349722 -0.904325  0.443206
c   -0.017991  0.032925  0.274248  0.326454 -0.108982  0.567472
d    2.363533 -1.676141  0.562893  0.967338 -1.071719 -0.321113
e    1.921324  0.110705  0.023244 -0.432196  0.172972 -0.50368

Now you can use xs to slice the dateframe based on levels.

df.xs('location1',level='loc',axis=1)

S        S1        S2        S3
a -1.245988  0.858071 -1.433669
b  1.132016  0.318813  0.949564
c -0.017991  0.032925  0.274248
d  2.363533 -1.676141  0.562893
e  1.921324  0.110705  0.02324

df.xs('S1',level='S',axis=1)

loc  location1  location2
a    -1.245988   0.105300
b     1.132016  -0.349722
c    -0.017991   0.326454
d     2.363533   0.967338
e     1.921324  -0.43219
Answered By: kanatti

To create header as a list of arrays dynamically, np.repeat and np.tile may be used to repeat the base lists/arrays in specific ways. So

loc = ['location', 'location2']
S = ['S1', 'S2', 'S3']

header = [np.repeat(loc, len(S)), np.tile(S, len(loc))]
#         ^^^ repeat `loc` 3 times   ^^^^ duplicate `S` twice

df = pd.DataFrame(np.random.randn(5, 6), columns=header)

result

However, it turns out that constructing a MultiIndex column this way is over 4 times slower than through pd.MultiIndex.from_product.

loc = [f'location{i}' for i in range(100)]
S = [f'S{i}' for i in range(100)]
df = pd.DataFrame(np.random.rand(5,10000))

%timeit df.set_axis([np.repeat(loc, len(S)), np.tile(S, len(loc))], axis=1)
# 6.07 ms ± 286 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)

%timeit df.set_axis(pd.MultiIndex.from_product([loc, S]), axis=1)
# 1.28 ms ± 113 µs per loop (mean ± std. dev. of 7 runs, 1,000 loops each)
Answered By: cottontail