get current function name inside that function using python

Question

For my logging purpose i want to log all the names of functions where my code is going

Does not matter who is calling the function , i want the the function name in which i declare this line

import inspect

def whoami():
    return inspect.stack()[1][3]

def foo():
    print(whoami())

currently it prints foo , i want to print whoami

Asked By: John Kaff

||

Source

Answer 1

You probably want inspect.getframeinfo(frame).function:

import inspect

def whoami(): 
    frame = inspect.currentframe()
    return inspect.getframeinfo(frame).function

def foo():
    print(whoami())

foo()

prints

whoami

Answered By: user707650

Answer 2

For my logging purpose i want to log all the names of functions where my code is going

Have you considered decorators?

import functools
def logme(f):
    @functools.wraps(f)
    def wrapped(*args, **kwargs):
        print(f.__name__)
        return f(*args, **kwargs)
    return wrapped


@logme
def myfunction():
    print("Doing some stuff")

Answered By: Eric

Answer 3

Actually, Eric’s answer points the way if this is about logging:

For my logging purpose i want to log all the names of functions where my code is going

You can adjust the formatter to log the function name:

import logging               

def whoami():
    logging.info("Now I'm there")

def foo():
    logging.info("I'm here")
    whoami()
    logging.info("I'm back here again")

logging.basicConfig(
    format="%(asctime)-15s [%(levelname)s] %(funcName)s: %(message)s",
    level=logging.INFO)
foo()

prints

2015-10-16 16:29:34,227 [INFO] foo: I'm here
2015-10-16 16:29:34,227 [INFO] whoami: Now I'm there
2015-10-16 16:29:34,227 [INFO] foo: I'm back here again

Answered By: user707650

Answer 4

Call sys._getframe() to get a frame class instance. The f_code.co_name member holds the function name.

sys._getframe(0).f_code.co_name

Add a simple helper function func_name() to wrap the call

import sys

def func_name(): 
    return sys._getframe(1).f_code.co_name

def func1():
    print(func_name())

func1()  # prints 'func1'

Answered By: JamesThomasMoon

Answer 5

This simple reusable method returns a name of the caller/parent function:

def current_method_name():
    # [0] is this method's frame, [1] is the parent's frame - which we want
    return inspect.stack()[1].function

Example:

def whoami():
    print(current_method_name())

whoami()

-> output is whoami

Answered By: Filip Happy

Answer 6

Adding an answer here as it can be useful to include the class name as well as the function.

This checks for self and cls convention, to include the class name.

def name_of_caller(frame=1):
    """
    Return "class.function_name" of the caller or just "function_name".
    """
    frame = sys._getframe(frame)
    fn_name = frame.f_code.co_name
    var_names = frame.f_code.co_varnames
    if var_names:
        if var_names[0] == "self":
            self_obj = frame.f_locals.get("self")
            if self_obj is not None:
                return type(self_obj).__name__ + "." + fn_name
        if var_names[0] == "cls":
            cls_obj = frame.f_locals.get("cls")
            if cls_obj is not None:
                return cls_obj.__name__ + "." + fn_name
    return fn_name

Answered By: ideasman42

get current function name inside that function using python

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