How do I find the maximum (larger, greater) of 2 numbers?
Question:
I have two variables value and run:
value = -9999
run = problem.getscore()
How can I find out which one is greater, and get the greater value?
See also Find the greatest (largest, maximum) number in a list of numbers – those approaches work (and are shown here), but two numbers can also be compared directly.
Answers:
max(number_one, number_two)
You can use max(value, run)
The function max takes any number of arguments, or (alternatively) an iterable, and returns the maximum value.
max(value,run)
should do it.
Use the builtin function max.
Example:
max(2, 4) returns 4.
Just for giggles, there’s a min as well…should you need it. 😛
Just for the fun of it, after the party has finished and the horse bolted.
The answer is: max() !
I noticed that if you have divisions it rounds off to integer, it would be better to use:
c=float(max(a1,...,an))/b
Sorry for the late post!
numberList=[16,19,42,43,74,66]
largest = numberList[0]
for num2 in numberList:
if num2 > largest:
largest=num2
print(largest)
gives largest number out of the numberslist without using a Max statement
(num1>=num2)*num1+(num2>num1)*num2 will return the maximum of two values.
You could also achieve the same result by using a Conditional Expression:
maxnum = run if run > value else value
a bit more flexible than max but admittedly longer to type.
# Python 3
value = -9999
run = int(input())
maxnum = run if run > value else value
print(maxnum)
There are multiple ways to achieve this:
- Custom method
def maximum(a, b):
if a >= b:
return a
else:
return b
value = -9999
run = problem.getscore()
print(maximum(value, run))
- Inbuilt max()
value = -9999
run = problem.getscore()
print(max(value, run))
- Use of ternary operator
value = -9999
run = problem.getscore()
print(value if value >= run else run)
But as you mentioned you are looking for inbuilt so you can use max()
I have two variables value and run:
value = -9999
run = problem.getscore()
How can I find out which one is greater, and get the greater value?
See also Find the greatest (largest, maximum) number in a list of numbers – those approaches work (and are shown here), but two numbers can also be compared directly.
max(number_one, number_two)
You can use max(value, run)
The function max takes any number of arguments, or (alternatively) an iterable, and returns the maximum value.
max(value,run)
should do it.
Use the builtin function max.
Example:
max(2, 4) returns 4.
Just for giggles, there’s a min as well…should you need it. 😛
Just for the fun of it, after the party has finished and the horse bolted.
The answer is: max() !
I noticed that if you have divisions it rounds off to integer, it would be better to use:
c=float(max(a1,...,an))/b
Sorry for the late post!
numberList=[16,19,42,43,74,66]
largest = numberList[0]
for num2 in numberList:
if num2 > largest:
largest=num2
print(largest)
gives largest number out of the numberslist without using a Max statement
(num1>=num2)*num1+(num2>num1)*num2 will return the maximum of two values.
You could also achieve the same result by using a Conditional Expression:
maxnum = run if run > value else value
a bit more flexible than max but admittedly longer to type.
# Python 3
value = -9999
run = int(input())
maxnum = run if run > value else value
print(maxnum)
There are multiple ways to achieve this:
- Custom method
def maximum(a, b): if a >= b: return a else: return b value = -9999 run = problem.getscore() print(maximum(value, run))
- Inbuilt max()
value = -9999 run = problem.getscore() print(max(value, run))
- Use of ternary operator
value = -9999 run = problem.getscore() print(value if value >= run else run)
But as you mentioned you are looking for inbuilt so you can use max()