How to divide without remainders on Python

Question

In this code i am trying to randomly create division questions for primary school age (10 years) so I don’t want any remainders when it dividies. This is the code I have, but I am unsure on how to do the divide thing.

     for i in range (0,2) :
         import random
         number1 = random.randint (20,30)
         number2 = random.randint (2,5)
         answer4 = (number1 / number2)
         question4 = int(input('What is %d / %d?: ' %(number1, number2)))
         if question4 == answer4:
             print ('Well done')
             score += 1
         else:
             print ('Wrong! The answer is %d' %(answer4))
     print ('You have finished the quiz! Well done!')
     print ('Your overall score is %d out of 10' %score)

This is part of a part of a bigger quiz with other questions, but I was unsure of this part, so any help would be welcomed.

Asked By: clare.python

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Source

Answer 1

You can do 5//2 and get 2 instead of the 2.5 you’d get with 5/2.

As long as you’re in Python 3
, you can also use floor(5/2).

Both ways of doing it give you the floor-rounded answer.

Answered By: Tyler Kaminsky

Answer 2

In python 3, the standard division operator / will do “real” division, while the // operator will do integer division.

Answered By: Chad S.

Answer 3

Simply randomize the number2 and the answer, then multiply to get number 1

number2 = random.randint(2,5)
answer4 = random.randint(20//number2, 30//number2)
number1 = number2*answer4

Answered By: pseudoDust

Answer 4

Use multiplication to arrive at the number.

import random as r
for i in range(0,2):
    num1 = r.randrange(2,6)
    num2 = r.randrange(2,6)
    print ("What is {}/{}".format(num1*num2,num2))
    if int(input()) == num1:
       print("Correct")
    else:
       print("Wrong, the answer is {}".format(num1))

With this, the quotient will always be an integer.

Answered By: intboolstring

How to divide without remainders on Python

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