How to change status of JsonResponse in Django

Question

My API is returning a JSON object on error but the status code is HTTP 200:

response = JsonResponse({'status': 'false', 'message': message})
return response

How can I change the response code to indicate an error?

Asked By: Dhanushka Amarakoon

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Source

Answer 1

Return an actual status

JsonResponse(status=404, data={'status':'false','message':message})

Answered By: Sayse

Answer 2

JsonResponse normally returns HTTP 200, which is the status code for 'OK'. In order to indicate an error, you can add an HTTP status code to JsonResponse as it is a subclass of HttpResponse:

response = JsonResponse({'status':'false','message':message}, status=500)

Answered By: Selcuk

Answer 3

To change status code in JsonResponse you can do this :

response = JsonResponse({'status':'false','message':message})
response.status_code = 500
return response

Answered By: Pratik Gujarathi

Answer 4

Python built-in http library has new class called HTTPStatus which is come from Python 3.5 onward. You can use it when define a status.

from http import HTTPStatus
response = JsonResponse({'status':'false','message':message}, status=HTTPStatus.INTERNAL_SERVER_ERROR)

The value of HTTPStatus.INTERNAL_SERVER_ERROR.value is 500. When someone read your code it’s better define someting like HTTPStatus.<STATUS_NAME> other than define an integer value like 500. You can view all the IANA-registered status codes from python library here.

Answered By: Kushan Gunasekera

Answer 5

This answer from Sayse works but it’s undocumented. If you look at the source you find that it passes the remaining **kwargs to the superclass constructor, HttpStatus. However in the docstring they don’t mention that. I don’t know if it’s the convention to assume that keyword args will be passed to the superclass constructor.

You can also use it like this:

JsonResponse({"error": "not found"}, status=404)

I made a wrapper:

from django.http.response import JsonResponse

class JsonResponseWithStatus(JsonResponse):
    """
    A JSON response object with the status as the second argument.

    JsonResponse passes remaining keyword arguments to the constructor of the superclass,
    HttpResponse. It isn't in the docstring but can be seen by looking at the Django
    source.
    """
    def __init__(self, data, status=None, encoder=DjangoJSONEncoder,
                 safe=True, json_dumps_params=None, **kwargs):
        super().__init__(data, encoder, safe, json_dumps_params, status=status, **kwargs)

Answered By: Benjamin Atkin

How to change status of JsonResponse in Django

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