Find the indexes of all regex matches?

Question

I’m parsing strings that could have any number of quoted strings inside them (I’m parsing code, and trying to avoid PLY). I want to find out if a substring is quoted, and I have the substrings index. My initial thought was to use re to find all the matches and then figure out the range of indexes they represent.

It seems like I should use re with a regex like "[^"]+"|'[^']+' (I’m avoiding dealing with triple quoted and such strings at the moment). When I use findall() I get a list of the matching strings, which is somewhat nice, but I need indexes.

My substring might be as simple as c, and I need to figure out if this particular c is actually quoted or not.

Asked By: xitrium

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Source

Answer 1

This is what you want: (source)

re.finditer(pattern, string[, flags]) 
Return an iterator yielding MatchObject instances over all
non-overlapping matches for the RE pattern in string. The string is
scanned left-to-right, and matches are returned in the order found. Empty
matches are included in the result unless they touch the beginning of
another match.

You can then get the start and end positions from the MatchObjects.

e.g.

[(m.start(0), m.end(0)) for m in re.finditer(pattern, string)]

Answered By: Dave Kirby

Answer 2

This should solve your issue:

pattern=r"(?=("[^"]+"|'[^']+'))"

Then use the following to get all overlapping indices:

indicesTuple = [(mObj.start(1),mObj.end(1)-1) for mObj in re.finditer(pattern,input)]

Answered By: Omkar Rahane

Answer 3

To get indice of all occurences:

S = input() # Source String 
k = input() # String to be searched
import re
pattern = re.compile(k)
r = pattern.search(S)
if not r: print("(-1, -1)")
while r:
    print("({0}, {1})".format(r.start(), r.end() - 1))
    r = pattern.search(S,r.start() + 1)

Answered By: Be Champzz

Find the indexes of all regex matches?

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