python recv() and eval()

Question

can someone please help me understand this code

clientsock.send("Welcome to Maths_Server 1.0n")

try:
    clientsock.send("Enter the first number, so I can EVALuate it:n")
    firstNum = eval(clientsock.recv(1024))
    firstNum = firstNum + firstNum + ord(flag[4]) + ord(flag[8]) + ord(flag[5])
    clientsock.send("Enter the second number, so I can EVALuate it:n")
    secondNum = eval(clientsock.recv(1024))
    if secondNum == firstNum:
        clientsock.send("The flag is: " + flag + "n")
        firstNum = 0
        secondNum = 0
except:
    pass

clientsock.close()

i want to know what does recv() does and how can i make the if statement true

Asked By: AdoobII

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Source

Answer 1

Well, you can’t determine the firstNum value because it’s inputted by the user, so you input a random number into the firstNum, then for the secondNum you enter firstNum, so what this does is the eval() takes the firstNum value and convert it into string for the secondNum which will make the if-statement true. Hope this works out.

Answered By: adib

Answer 2

The answer to this riddle is this is actually the server code, but you need to make a client which will connect to that server, and produce equal results to get the flag.

Answered By: Guy

python recv() and eval()

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