Plotting percentage in seaborn bar plot

Question:

For a dataframe

import pandas as pd
df=pd.DataFrame({'group':list("AADABCBCCCD"),'Values':[1,0,1,0,1,0,0,1,0,1,0]})

I am trying to plot a barplot showing percentage of times A, B, C, D takes zero (or one).

I have a round about way which works but I am thinking there has to be more straight forward way

tempdf=df.groupby(['group','Values']).Values.count().unstack().fillna(0)
tempdf['total']=df['group'].value_counts()
tempdf['percent']=tempdf[0]/tempdf['total']*100

tempdf.reset_index(inplace=True)
print tempdf

sns.barplot(x='group',y='percent',data=tempdf)

If it were plotting just the mean value, I could simply do sns.barplot on df dataframe than tempdf. I am not sure how to do it elegantly if I am interested in plotting percentages.

Thanks,

Asked By: PagMax

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Answers:

You could use your own function in sns.barplot estimator, as from docs:

estimator : callable that maps vector -> scalar, optional
Statistical function to estimate within each categorical bin.

For you case you could define function as lambda:

sns.barplot(x='group', y='Values', data=df, estimator=lambda x: sum(x==0)*100.0/len(x))

enter image description here

Answered By: Anton Protopopov

You can use the library Dexplot, which has the ability to return relative frequencies for categorical variables. It has a similar API to Seaborn. Pass the column you would like to get the relative frequency for to the count function. If you would like to subdivide this by another column, do so with the split parameter. The following returns raw counts.

import dexplot as dxp
dxp.count('group', data=df, split='Values')

enter image description here

To get the relative frequencies, set the normalize parameter to the column you want to normalize over. Use True to normalize over the overall total count.

dxp.count('group', data=df, split='Values', normalize='group')

enter image description here

Normalizing over the 'Values' column would produce the following graph, where the total of all the ‘0’ bars are 1.

dxp.count('group', data=df, split='Values', normalize='Values')

enter image description here

Answered By: Ted Petrou

You can use Pandas in conjunction with seaborn to make this easier:

import pandas as pd
import seaborn as sns

df = sns.load_dataset("tips")
x, y, hue = "day", "proportion", "sex"
hue_order = ["Male", "Female"]

(df[x]
 .groupby(df[hue])
 .value_counts(normalize=True)
 .rename(y)
 .reset_index()
 .pipe((sns.barplot, "data"), x=x, y=y, hue=hue))

enter image description here

Answered By: mgoldwasser

You can follow these steps so that you can see the count and percentages on top of the bars in your plot. Check the example outputs down below

with_hue function will plot percentages on the bar graphs if you have the ‘hue’ parameter in your plots. It takes the actual graph, feature, Number_of_categories in feature, and hue_categories(number of categories in hue feature) as a parameter.

without_hue function will plot percentages on the bar graphs if you have a normal plot. It takes the actual graph and feature as a parameter.

def with_hue(plot, feature, Number_of_categories, hue_categories):
    a = [p.get_height() for p in plot.patches]
    patch = [p for p in plot.patches]
    for i in range(Number_of_categories):
        total = feature.value_counts().values[i]
        for j in range(hue_categories):
            percentage = '{:.1f}%'.format(100 * a[(j*Number_of_categories + i)]/total)
            x = patch[(j*Number_of_categories + i)].get_x() + patch[(j*Number_of_categories + i)].get_width() / 2 - 0.15
            y = patch[(j*Number_of_categories + i)].get_y() + patch[(j*Number_of_categories + i)].get_height() 
            ax.annotate(percentage, (x, y), size = 12)
    plt.show()

def without_hue(plot, feature):
    total = len(feature)
    for p in ax.patches:
        percentage = '{:.1f}%'.format(100 * p.get_height()/total)
        x = p.get_x() + p.get_width() / 2 - 0.05
        y = p.get_y() + p.get_height()
        ax.annotate(percentage, (x, y), size = 12)
    plt.show()

enter image description here

enter image description here

Answered By: Deepak Natarajan