How to get (sub)class name from a static method in Python?

Question:

If I define:

class Bar(object):

    @staticmethod
    def bar():
        # code
        pass

class Foo(Bar):
    # code
    pass

Is it possible for a function call Foo.bar() to determine the class name Foo?

Asked By: Jean-Pierre Chauvel

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Source

Answers:

Replace the staticmethod with a classmethod. This will be passed the class when it is called, so you can get the class name from that.

class Bar(object):

    @classmethod
    def bar(cls):
        # code
        print cls.__name__

class Foo(Bar):
    # code
    pass

>>> Bar.bar()
Bar

>>> Foo.bar()
Foo
Answered By: Dave Kirby

If you need to find the class information, the appropriate way is to use @classmethod.

class Bar(object):
    @classmethod
    def bar(cls):
        # code
        print(cls.__name__)

class Foo(Bar):
    # code
    pass

Now your bar method has a reference to the class as cls which is the actual class of the caller. And as shown in the code, cls.__name__ is the name of the class you are looking for.

>>> Foo.bar()
Foo
>>> Bar.bar()
Bar
Answered By: Muhammad Alkarouri

As option, if you need determine class from staticmethod (not classmethod) I guess following code could be helpful:

class Bar(object):
    @staticmethod
    def bar():
        pass


class Foo(Bar):
    pass


foo_instance = Foo()
bar_static_function = foo_instance.bar
class_name = bar_static_function.__qualname__.split(".")[0]
print(class_name)  # Foo
Answered By: Yuriy Leonov